Question

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我有这个查询，假设只取出typei列的计数，但是当我运行它时，它会拉出整个数据库的计数，并且不遵守where子句规则......

SELECT [type], typei, vtdate, count (typei) as count
FROM vtindex
where typei is not null or typei <> '#'
and vtdate between '2016/06/01' and '2016/06/30'
GROUP BY
[type], Typei, vtdate
HAVING
COUNT(typei) > 1

这个想法是用户输入日期垃圾邮件，并为他们提供特定日期垃圾邮件的typei计数

感谢...

Answer 1

在GROUP BY - Clause中，只有你想要分组的列，而不是你要计算或总和的列。所以试试吧：

SELECT [type], vtdate, count(typei) as count
FROM vtindex
WHERE typei IS NOT NULL OR typei <> '#'
   and vtdate between '2016/06/01' and '2016/06/30'
GROUP BY [type], vtdate
HAVING count(typei) > 1

Answer 2

添加括号以正确过滤记录。

目前，where子句按以下顺序验证

Where typei IS NOT NULL OR (typei <> '#'
  and vtdate between '2016/06/01' and '2016/06/30')

但你需要这个

Where (typei IS NOT NULL OR typei <> '#')
  and vtdate between '2016/06/01' and '2016/06/30'

Answer 3

试试这个：

SELECT [type], typei, count (typei) as count
FROM vtindex
where typei is not null or typei <> '#'
and vtdate between '2016/06/01' and '2016/06/30'
GROUP BY
[type], Typei
HAVING
COUNT(typei) > 1

想法是删除除Typei之外的其他字段并按其分组。

祝你好运！

Answer 4

我认为它应该是这样的;）

SELECT [type], typei, vtdate, count (typei) as count
FROM vtindex
where (typei is not null or typei <> '#')
and vtdate between '2016/06/01' and '2016/06/30'
GROUP BY
[type], Typei, vtdate
HAVING
COUNT(typei) > 1

如果没有这个括号，当typei不为空时，将不会计算其他条件。

算不遵守where子句

4 个答案: