方法
static List<Tuple<string, int>> F(string root, int rootLevel)
{
List<Tuple<string, int>> result = new List<Tuple<string, int>>();
foreach (var item in Directory.EnumerateDirectories(root))
{
try
{
result.Add(new Tuple<string, int>(item, rootLevel + 1));
result.AddRange(F(item, rootLevel + 1));
}
catch (UnauthorizedAccessException ex)
{
string tried = "";
}
}
return result;
}
然后在构造函数中使用它
var dirs = F(textBox3.Text, 0);
var deep = (from d in dirs
orderby d.Item2 descending
select d).FirstOrDefault().Item2;
Search_Engine se = new Search_Engine();
se.Run();
这种情况下的问题是se.Run();
应该返回string[]
。
dirs
是List<Tuple<string, int>>
std::vector<std::string> strVect;
auto pushToVector = [strVect] () {
strVect.push_back(std::string("Hi"));
};
pushToVector ();
答案 0 :(得分:4)
你可以这样做:
var dirs = F(textBox3.Text, 0);
Search_Engine se = new Search_Engine();
se.Run(dirs.Select(item => item.Item1).ToArray());
答案 1 :(得分:0)
您可以自己轻松完成,例如:
var length = dirs.Count();
string[] array = new string[length];
for(int i = 0; i < length; i++)
{
array[i] = dirs[i].Item1;
}
//array is now what you want