Question

我正在尝试使用一行代码将id与id_list匹配，以下似乎无法正常工作，我该如何解决？

id  = 77bb1b03
id_list = ['List of devices attached ', '572ea01e\tdevice', '77bb1b03\tdevice', '']
if id in id_list:
     print "id present"
else:
     print "id not present"

Answer 1

您不是在相等上匹配，而是在列表中值的子字符串上匹配，假设您只想匹配开头：
注意：假设id实际上是一个字符串，因为它不是有效的文字。

id  = '77bb1b03'
id_list = ['List of devices attached ', '572ea01e\tdevice', '77bb1b03\tdevice', '']
if any(i.startswith(id) for i in id_list):
    print "id present"
else:
    print "id not present"

Answer 2

首先，修复你的代码：

id  = "77bb1b03" # needs to be a string
id_list = ['List of devices attached ', '572ea01e\tdevice', '77bb1b03\tdevice', '']

然后遍历列表并单独比较每个字符串：

for s in id_list:
    if id in s:
        print "id %s present"%id
        break
else:
    print "id %s not present"%id

Answer 3

检查出来：
你要求的单个衬垫和id是一个字符串！

>>> from __future__ import print_function
... id  = '77bb1b03'
... id_list = ['List of devices attached ', '572ea01e\tdevice', '77bb1b03\tdevice', '']
... [print(item, 'ID present') for item in id_list if item and item.find(id)!=-1]
77bb1b03    device ID present

感谢左侧的@Achampion - ＆gt;正确执行！

Answer 4

一种令人讨厌的，模糊的，较慢的替代方案。 id var似乎是列表项的前缀，但不确定是否需要找到id＆＃34;某处＆＃34;在列表元素中。

id  = 77bb1b03
id_list = ['List of devices attached ', '572ea01e\tdevice', '77bb1b03\tdevice', '']
if len(filter(lambda id_list_item: id_list_item.find(id) >=0 , id_list)):
    print "id present"
else:
    print "id not present"

如何将元素与列表匹配？

4 个答案: