Question

我正在尝试创建一个登录系统而我收到此数据库错误

您的SQL语法有错误;检查与MariaDB服务器版本对应的手册，以便在“SET last_activity = 1467333267，user_data ='a：3：{s：9：\”user_data \“; s附近使用正确的语法：0：\“\”'在第1行

UPDATE SET last_activity = 1467333267，user_data ='a：3：{s：9：\“user_data \”; s：0：\“\”; s：5：\“ email \“; s：16：\”ocyl28@yahoo.com \“; s：12：\”is_logged_in \“; i：1;}'WHERE session_id ='570d7ba3d7f11a9a35264ed276368480'

文件名：C：/xampp/htdocs/CodeIgniter/system/database/DB_driver.php

行号：691

这是我的控制器代码：

class Template extends CI_Controller {


    public function index()
    {
        $this->login();
    }   

    public function login()
    {
        $this->load->view('Login Template.php');
    }

    public function admin()
    {
        if ($this->session->userdata('is_logged_in')) {
            $this->load->view('Template 3.php');    
        }
        else {
            echo 'cannot login';
        }   
    }

    public function login_validation()
    {
        $this->load->library('form_validation');

        $this->form_validation->set_rules('email' , 'Email', 'required|trim|callback_validate_credentials');
        $this->form_validation->set_rules('password' , 'Password', 'required|md5|trim');

        if ($this->form_validation->run()) {
            $data = array (
                'email' => $this->input->post('email'),
                'is_logged_in' => 1
                );

            $this->session->set_userdata($data);
            redirect('template/admin');
        }
        else 
        {

            echo 'fail';
        }

    }

    public function validate_credentials()
    {
        $this->load->model('users');

        if ($this->users->can_log_in()) {
            return true;
        }
        else
        {
            $this->form_validation->set_message('validate_credentials', 'fail to login');
            return false;
        }
    }



    public function about()
    {
        $this->load->view('About this site.php');
    }

    public function logout()
    {
        $this->session->sess_destroy();
        redirect('template/login');
    }

这是我的型号代码：

class Users extends CI_Model
{

    public function can_log_in()
    {
        $this->db->where('email', $this->input->post('email'));
        $this->db->where('password', md5($this->input->post('password')));

        $query = $this->db->get('registered_users');

        if ($query->num_rows() == 1) {
            return true; 
        }
        else 
        {
            return false;
        }
    }

Answer 1

SQL语句中缺少表名。

如何处理CodeIgniter错误号1064？

1 个答案: