Question

我有一张图片表，每张图片都与画廊表有很多关系。我正在尝试使用org.hibernate.Criteria来返回链接给定列表库的所有图像。

我一直在尝试以下操作，在这里我遍历画廊列表并为每个画廊创建一个新的createCriteria（例如，每个必需画廊一个内部连接），这只适用于一个画廊。但是，当我尝试多次时，我收到org.hibernate.QueryException: duplicate association path: galleries错误...

ImagesDAOCustom.java

public Images getRandomImagesInGallerys(String[] galleryList) {             
        Session session = sessionFactory.getCurrentSession();
        Criteria criteria = session.createCriteria(Images.class, "image");
        // We want an image that is part of all galleries so we need to create
        // a join per gallery.
        for (String gallery: galleryList) {
            criteria.createCriteria("image.galleries", gallery);
            criteria.add(Restrictions.eq(gallery + ".name",gallery));
        }
        criteria.setProjection(Projections.distinct(Projections.property("id")));
        List<Integer> imageIdList = criteria.list();

        Images result;
        if (imageIdList.size() > 0) {
            int index = rand.nextInt(imageIdList.size());
            result = imagesDAO.findOne(imageIdList.get(index));
        } else {
            result = null;
        }
        return result;
    }

Images.java

public class Images  {

    @Id
    @GeneratedValue
    @Column(name="ugc_images_id")
    private int id;

    @JsonIgnore
    @JsonView(Views.Internal.class)
    @ManyToMany(fetch = FetchType.LAZY)
    @JoinTable(name="ugc_image_galleries", joinColumns={@JoinColumn(name="image_id")}, inverseJoinColumns={@JoinColumn(name="gallery_id")})
    private Set<Galleries> galleries = new HashSet<>();

    ...
}

Galleries.java

public class Galleries }

    @Id
    @GeneratedValue
    @Column(name="ugc_galleries_id")
    private int id;

    @JsonManagedReference
    @ManyToMany(mappedBy="galleries")    
    private Set<Images> images = new HashSet<>();

    @Column(name="name")
    private String name;

    ...

}

Answer 1

我遇到了同样的问题，我搜索了几个小时。

这对我有用：

public Images getRandomImagesInGallerys(String[] galleryList) {

    String query = "from Images ";
    boolean first = true;

    for(String string : galleryList) {
        if(first){
            query+="where '"+string+"' member of galleries ";
            first=false;
        } else {
            query+="or '"+string+"' member of galleries ";
        }
    }

    entityManager.createQuery(query, Images.class).getResultList();
}

希望对某人有所帮助。

迭代创建createCriteria。获取错误org.hibernate.QueryException：重复的关联路径

1 个答案: