如何将一维红宝石阵列组合成二维数组？

Question

我有两个数组：

• 学校名称数组
• 学校阵营

假设学校名称数组为：[name1, name2, name3]和slug名称为：[slug1, slug2, slug3]。

在ruby中，我如何制作数组[[name1, slug1], [name2, slug2], [name3, slug3]]。

我对此事的尝试有点javascript-ish：

<% var schoolSelect = [];
for (var i=0; i<@schools.length; i++)
    schoolSelect[i] = [@schools.pluck(:name)[i], @schools.pluck(:slug)[i]]; %>

Answer 1

您将使用{{3}}，例如：

% echo 'Voldemort' > badwords.txt
% bfg --replace-text badwords.txt myrepo.git

Answer 2

建议您考虑使用该数据结构的哈希值

schools = ["first", "second", "third"]
slugs = ["a", "b", "c"]
school_slugs = {}

(0..2).each do |position|
  school_slugs[schools[position]] = slugs[position]
end
# => 0..2
school_slugs
# => {"first" => "a", "second" => "b", "third" => "c"}

如果你使用Arup的方法，你也可以把它变成哈希，即

[["name1", "slug1"], ["name2", "slug2"], ["name3", "slug3"]].to_h

# => {"name1"=>"slug1", "name2"=>"slug2", "name3"=>"slug3"} 

Answer 3

names = %w(name1 name2 name3)
slugs = %w(slug1 slug2 slug3)

每当你有两个相同大小的数组时，就像这里一样，

names.zip(slugs)
  #=> [["name1", "slug1"], ["name2", "slug2"], ["name3", "slug3"]]

和

[names, slugs].transpose
  #=> [["name1", "slug1"], ["name2", "slug2"], ["name3", "slug3"]]

可以互换。