Question

我有一个复杂的对象，如：

public class BusinessUnit
{
        public TradingDesk TradingDesk { get; }
        public string Division { get; }

        public BusinessUnit(string division, TradingDesk tradingDesk)
        {
            Division = division;
            TradingDesk = tradingDesk;
        }
}

我想将其映射到平面类型：

public class Row
{
   //TradingDesk properties
   public string TraderFirstName { get; set; }
   public string TraderLastName { get; set; }
   public string TradingDeskName { get; set; }

   public string Division { get; set; }
}

我已为AutoMapper配置了TradingDesk：

CreateMap<TradingDesk, Row>().ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.Name));

所以以下测试正在通过：

[Test]
public void Should_Map_TradingDesk_To_Row()
{
    var tradingDesk = Fixture.Create<TradingDesk>();

    var mapped = AutoMapper.Map<Row>(tradingDesk);

    mapped.TradingDeskName.Should()
            .Be(tradingDesk.Name);
    mapped.TraderFirstName.Should()
            .Be(tradingDesk.Trader.FirstName);
    mapped.TraderLastName.Should()
            .Be(tradingDesk.Trader.LastName);
}

但是当我尝试将BusinessUnit映射到Row时，我不得不为AutoMapper重新配置TradingDesk：

CreateMap<BusinessUnit, Row>()
   .ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.TradingDesk.Name))
   .ForMember(vm => vm.TraderFirstName, op => op.MapFrom(src => src.TradingDesk.Trader.FirstName))
   .ForMember(vm => vm.TraderLastName, op => op.MapFrom(src => src.TradingDesk.Trader.LastName));

我希望AutoMapper应该使用已配置的来源＆amp;映射TradingDesk时需要将Row映射到BusinessUnit的目标类型映射。这样，我可以构建从最小到最大类型的配置，同时展平复杂对象，而无需为展平类型中的每个单独成员定义映射。

Answer 1

实际语法可能有所不同，因为我以静态方式使用AutoMapper，但原则保持不变：

Mapper.CreateMap<BusinessUnit, Row>()
      .ConvertUsing(source => Mapper.Map<TradingDesk, Row>(source.TradingDesk));

Answer 2

首先，我认为您的交易台地图只是

CreateMap<TradingDesk, Row>();

如果内存对我有用，因为你的目标成员在“。”时匹配源成员名称。删除后，您不需要明确指定它。

如果您将Row类更改为此

public class Row
{
   //TradingDesk properties
   public string TradingDeskTraderFirstName { get; set; }
   public string TradingDeskTraderLastName { get; set; }
   public string TradingDeskName { get; set; }

   public string Division { get; set; }
}

你的地图将是

CreateMap<BusinessUnit, Row>();

如果您永远不会映射到TradingDesk，请删除该地图。

如果在某个配置文件中定义了这个，您也可以说

RecognizePrefixes("TradingDesk");

然后您无需更改Row类。

Answer 3

如果您不想创建特殊转换器或属性解析器，则可以在主对象的映射之后执行第二次映射，例如：

Mapper.Initialize(cfg =>
{
    cfg.CreateMap<TradingDesk, Row>()
        .ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.Name));
    cfg.CreateMap<BusinessUnit, Row>()
        .AfterMap((businessUnit, row) => { Mapper.Map(businessUnit.TradingDesk, row); });
});

var source = new BusinessUnit("division", new TradingDesk { TraderFirstName = "FirstName", TraderLastName = "LastName", Name = "DeskName" });

var dest = Mapper.Map<Row>(source);

在这种情况下，已映射对象而不创建新实例。

在AutoMapper中将复杂类型映射到平面类型

3 个答案: