Question

在数据库中，我有以下结构

id | following_id | followed_id
1  |     3        |    1
2  |     2        |    1

I have user model and it looks like this 

public function userFollows()
    {
        return $this->belongsToMany('Diskourse\Models\User','followers','following_id','followed_id');

}

public function userIsFollowed()
{
    return $this->belongsToMany('Diskourse\Models\User','followers','followed_id','following_id');
}

public function followers()
{
   return $this->userIsFollowed->merge($this->userFollows);
}


And at last view looks like this 


            <h4>Followers</h4>

            @if(!$user->followers()->count())

            <p>No followers</p>

            @endif
                @foreach($user->followers() as $follower)

                    @include('user/partials/userblock')

                @endforeach
            </div>
        </div>

如果它工作，它应该显示用户3和2作为1的跟随者。而是当前用户配置文件块显示两次。请帮助!!!!

Answer 1

exit()部分寻找变量userblock吗？因为仍然设置为当前用户。我会用这个：

$user

这将重复每个关注者的@each('user.partials.userblock', $user->userFollows, 'user')视图，将关注者传递为userblock

在laravel中，我将当前用户视为自己的追随者，而不是追随者

1 个答案: