Question

实体类1

null does not have method open

实体类2

       @Entity
       @Table(name = "TICKETS")
       public class Ticket {

       ....

      @Column(name = "MERCHANT_NBR")
      private String merchant_nbr;

      @ManyToOne(fetch = FetchType.LAZY)
      @JoinColumn(name = "merchant_nbr", nullable = false)
      private Merchant merchant;

     @ManyToOne(fetch = FetchType.LAZY)
     @JoinColumn(name ="merchantNBR", nullable = false)
     private merchantDetails merchantDetails;

错误地给出了...无效的列'merchantNBR'。但是我有一个名称的列。

  @Entity
  @Table(name="MERCHANT_DETAILS")
  public class merchantDetails {

    @Id
    @Column(name="MERCHANT_NBR")
    private String merchantNBR;

    @OneToMany(fetch = FetchType.LAZY)
    private Set<Ticket> ticket;

Answer 1

所以它是一个连接列而不是列，为此您必须使用正确的注释来连接两个实体@JoinColumn 看到这可能会有所帮助

@joinColumn(name = "MERCHANT_NBR" ,referencedColumnName="merchantNBR")
      private String merchant_nbr;

这里我认为您已经从

更改了权限类2中的列名

@Column(name="MERCHANT_NBR") to `@Column(name="merchantNBR")`

com.microsoft.sqlserver.jdbc.SQLServerException：无效的列名称'xxx'

1 个答案: