Question

我目前正在为餐馆申请。我正在处理的代码的想法是，它从组合框中获取名称，并将收据插入数据库，其中包含正在处理它的人员的员工编号。我正在努力做的代码是：

    RestaurantOrder sqlRestaurantOrder = new RestaurantOrder();
    ActionListener printReceiptListner;
    printReceiptListner = (ActionEvent) -> {
        int ID = Integer.parseInt(input1.getText());
        try {
            SystemManager manager = new SystemManager();
            ResultSet rs = manager.stmt.executeQuery(sqlRestaurantOrder.setIdSql(ID));

            while (rs.next()) {

                double totalPrice = rs.getDouble("sumprice");
                if (ID > 0) {
                    Receipt receiptSql = new Receipt();
                    String firstName = (String) cb.getSelectedItem();
                    String checkoutDate = new SimpleDateFormat("yyyyMMdd").format(Calendar.getInstance().getTime());
                    ResultSet rs2 = manager.stmt.executeQuery(receiptSql.getEmployeeId(firstName));
                    int employeeId = rs2.getInt("id");

                    while (rs2.next()) {

                    Receipt receiptSql2 = new Receipt();
                    ResultSet rs3 = manager.stmt.executeQuery(receiptSql2.SetStatusReceipt(employeeId, checkoutDate, ID, totalPrice));
                    while (rs3.next()) {
                    }
                    }

                }
            }

        } catch (SQLException k) {
            JOptionPane.showMessageDialog(null, k.getMessage());
        }
    };

陈述是：

public class Receipt {

    public String sql;
    public String sql2;

    public String getEmployeeId(String firstName){
        return sql2 = "SELECT id FROM employee WHERE firstName = '" + firstName + "';";
    }

    public String SetStatusReceipt(int employeeId, String checkoutDate, int id, double totalPrice){
        return sql = "INSERT INTO `receipt` (`employeeId`, `price`, `restaurantOrderId`, `checkoutDate`) VALUES (" + employeeId + " , " + totalPrice + ", " + id + ", " + checkoutDate + ");";
    };

}

我在结果集开始之前收到了错误，我查看了它的意思但是我现在无法修复它。将不胜感激。

如果我忘记发布更重要的代码，请告诉我我会更新它

Answer 1

您必须先致电ResultSet.next()，然后才能访问ResultSet的字段。因此，您需要将employeeId的作业移至while循环：

while (rs2.next()) {
    int employeeId = rs2.getInt("id");

来自ResultSet.next()的文档：

ResultSet光标最初位于第一行之前;第一次调用方法next使第一行成为当前行;第二个调用使第二行成为当前行，依此类推。

在开始运行多个sql的结果集之前

1 个答案: