$sql = "
SELECT *
FROM teacher_uploads
where view_counts in (SELECT view_counts
from teacher_uploads
ORDER BY view_counts DESC
) and
subject_id = $subject_id";
现在我想获取所有最大view_counts 限制为2
答案 0 :(得分:1)
您可以使用join
:
SELECT tu.*
FROM teacher_uploads tu JOIN
(SELECT view_counts
FROM teacher_uploads
ORDER BY view_counts DESC
LIMIT 2
) ttu
ON tu.view_counts = ttu.view_counts
WHERE subject_id = $subject_id;
注意:您可能还需要子查询中的WHERE
子句。但是,这不是您问题中的查询。
答案 1 :(得分:-2)
$sql = "
SELECT *
FROM teacher_uploads
WHERE view_counts IN (SELECT view_counts
FROM teacher_uploads
ORDER
BY view_counts DESC )
AND subject_id = $subject_id
LIMIT 2"