Question

我有一个包含一些许可证的表，对于不同的许可证，存在基于网络的记录例如：许可证12345具有网络记录（＆＃39; 101＆＃39;，＆＃39; 102＆＃39;，＆＃39; 108＆＃39;）现在我想从网络中找出（＆＃39; 101＆＃39;＆＃39; 102＆＃39;＆＃39; 108＆＃39;，＆＃39; 113＆＃39;，＆＃39 ; 114＆＃39;），我的许可证丢失了所有网络，之后我们需要将现有许可证的数据复制到所有五个网络的丢失许可证中吗？

我已经在使用脚本了：看看

select license, count(*) data, network nt1 from x_pns_address
where network  in ('101','102', '108', '113', '114')
and license in ('110438','150275')
group by license, network
into temp sherin_1;

select distinct license, '101' netw from x_pns_address
where license in ('110438','150275')
into temp table1;

insert into  table1 select distinct license, 
'102' netw from x_pns_address
where license in ('110438','150275');
insert into  table1 select distinct license,
'108' netw from x_pns_address
where license in ('110438','150275');
insert into table1  select distinct license, 
'113' netw from x_pns_address
where license in ('110438','150275');
insert into  table1  select distinct license, 
'114' netw from x_pns_address
where license in ('110438','150275');

select distinct a.nt1,a.license,
b.netw  from sherin_1 a, table1 b
where a.license = b.license
and  a.nt1 <> b.netw
 ;

这就是我的意思：

 nt1 license      netw

   101 150275       102
   101 150275       108
   101 150275       113
   101 150275       114
   102 110438       101
   102 110438       108
   102 110438       113
   102 110438       114
   102 150275       101
   102 150275       108
   102 150275       113
   102 150275       114
   108 110438       101
   108 110438       102
   108 110438       113
   108 110438       114
   108 150275       101
   108 150275       102
   108 150275       113
   108 150275       114
   113 110438       101
   113 110438       102
   113 110438       108
   113 110438       114
   113 150275       101
   113 150275       102
   113 150275       108
   113 150275       114
   114 110438       101
   114 110438       102
   114 110438       108
   114 110438       113

Answer 1

对于SQL Server，您可以使用：

我用虚拟数据创建表。

CREATE TABLE #x_pns_address (
    network int,
    license int
)

INSERT INTO #x_pns_address VALUES
(101,12345),
(102,12345),
(108,12345),
(101,54321),
(102,54321),
(108,54321),
(113,54321),
(114,54321),
(101,98765),
(108,98765)

正如您所看到，许可54321拥有全部5个网络，而12345，98765获得了2和3。

然后我们运行：

INSERT INTO #x_pns_address
SELECT  p1.license,
        n.network
FROM (
    SELECT license --Here we get all licenses that missed any of the
    FROM #x_pns_address   --given numbers
    WHERE network IN (101,102,108,113,114)
    GROUP BY license
    HAVING COUNT(network) < 5
    ) as p1
CROSS JOIN ( --Cartesian join with license numbers we need
    SELECT * FROM (VALUES (101),(102),(108),(113),(114)) as t(network)
) as n
LEFT JOIN #x_pns_address x --and here we get only those that are not in main table
    ON x.network = n.network and x.license = p1.license
WHERE x.license  IS NULL

在#x_pns_address我们为许可12345，98765添加5行缺少网络：

license network
12345   113
12345   114
98765   102
98765   113
98765   114

我如何加入这些表格并获得所需的结果

1 个答案: