Question

这是我的触发器：

ALTER TRIGGER DONORINFO_INSERT 
ON [dbo].[DONORINFO] INSTEAD OF INSERT
AS
    DECLARE @sequence AS VARCHAR(50) = '' 
    DECLARE @tranLen VARCHAR(10)

    SET @sequence = (SELECT TOP 1 SUBSTRING([DONORID], 3, 8) 
                     FROM [dbo].[DONORINFO] 
                     ORDER BY [DONORID] DESC)

    IF (@sequence IS NULL OR @sequence = '')
    BEGIN           
        SELECT @sequence = REPLICATE('0', 7 ) + '1'                  
    END
    ELSE            
    BEGIN           
        SELECT @tranLen = LEN(@sequence)
        SELECT @sequence = @sequence + 1    
        SELECT @tranLen = ABS(@tranLen - LEN(CAST(@sequence AS INT)))
        SELECT @sequence =   REPLICATE('0', @tranLen) + @sequence
    END     

    DECLARE @DONORID AS [nvarchar](50) = 'DN' + CONVERT(VARCHAR, @sequence) 

    INSERT INTO [dbo].[DONORINFO] ([DONORID], [DONORNAME])
        SELECT @DONORID, inserted.DONORNAME
        FROM inserted

在脚本的第一行中，我正在阅读DONORINFO表，在该表中检查了唯一ID是否存在。之后，我将记录插入该表中。我第一次测试，插入到选择脚本工作，但第二次，它失败并发送和违反主键错误。

但是，如果我逐行插入测试，它就可以工作。

这是一行一行的插入脚本。

INSERT INTO [dbo].[DONORINFO] ([DONORID], [DONORNAME])
VALUES ('DN00000001', 'test')

如果我运行两次，记录将是这样的：

DONORID     DONORNAME   
---------------------
DN00000001  test    
DN00000002  test

这是插入到选择脚本中不起作用：

INSERT INTO [dbo].[DONORINFO] ([DONORID], [DONORNAME])
    SELECT
        '',
        [NameOfDonor] 
    FROM 
        [dbo].[_TEMPENDOWMENTFUND] AS ENDF
    WHERE 
        [ENDF].[NameOfDonor] NOT IN (SELECT [DONORNAME] 
                                     FROM [dbo].[DONORINFO])

_TEMPDOWMENTFUND是我创建的一个表，用于存储从Excel工作表迁移的数据，触发器的目的是为每个插入的工作表生成一个唯一的DONORID DONORINFO表。

现在我的问题是，我想在select语句中执行插入，这是一个多行插入，但是我很难搞清楚我创建的触发器出了什么问题。

任何帮助将不胜感激。感谢。

Answer 1

让@sequence完全int（并可能将其重命名为last_id），最后添加字符。

要编号行，请在ROW_NUMBER()的最终选择中使用INSERTED：

INSERT INTO [dbo].[DONORINFO] ([DONORID], [DONORNAME])
SELECT
  'DN' + REPLICATE('0', ABS(@len_you_need - LEN(t.generated_id))) + CAST (t.generated_id as varchar(100)),
  t.DONORNAME
FROM
(
SELECT
  i.DONORNAME, 
  @sequence+ROW_NUMBER()OVER(ORDER BY i.DONORNAME) as generated_id
FROM inserted i
) t

@len_you_need - 是您需要的DONORID长度。我想这可能是8个字符的常量。在你的来源中，你在这里计算：

SELECT @tranLen = LEN(@sequence)

t.rn是在上面给出的子查询中生成的“序列”值，它具有t别名。为清楚起见，将其重命名为generated_id。

这个区块：

BEGIN           
     SELECT @tranLen = LEN(@sequence)
     SELECT @sequence = @sequence + 1   
     SELECT @tranLen = ABS(@tranLen - LEN(CAST(@sequence AS INT)))
     SELECT @sequence =   REPLICATE('0', @tranLen) + @sequence
END

不再需要了。

Answer 2

这是完整的解决方案@ ivan-starostin帮助我回答。

ALTER TRIGGER DONORINFO_INSERT ON [dbo].[DONORINFO]
INSTEAD OF INSERT, UPDATE
AS
DECLARE @sequence AS VARCHAR(50) = '' 
DECLARE @tranLen VARCHAR(10)

SET @sequence = (SELECT TOP 1 SUBSTRING([DONORID], 3, 8) FROM [dbo].[DONORINFO] ORDER BY [DONORID] DESC)

IF (@sequence IS NULL OR @sequence = '')
BEGIN           
    SELECT @sequence = REPLICATE('0', 7 )
END
ELSE            
BEGIN           
     SELECT @tranLen = LEN(@sequence)
     SELECT @sequence = @sequence + 1   
     SELECT @tranLen = ABS(@tranLen - LEN(CAST(@sequence AS INT)))
     SELECT @sequence =   REPLICATE('0', @tranLen) + @sequence
END     


INSERT INTO [dbo].[DONORINFO] ([DONORID], [DONORNAME])
SELECT
  'DN' + REPLICATE('0', ABS(8 - LEN(t.generated_id))) + CAST (t.generated_id        as varchar(100)),
  t.DONORNAME
FROM
(
SELECT
  i.DONORNAME, 
  @sequence+ROW_NUMBER()OVER(ORDER BY i.DONORNAME) as generated_id
FROM inserted i
) t

所以如果我在下面运行那两个不同的insert into select ......

INSERT INTO [dbo].[DONORINFO] ([DONORNAME])
SELECT 
[NameOfDonor] 
FROM [dbo].[_TEMPENDOWMENTFUND] AS ENDF
WHERE [ENDF].[NameOfDonor] NOT IN (SELECT [DONORNAME] FROM [dbo].[DONORINFO])

INSERT INTO [dbo].[DONORINFO] ([DONORNAME])
SELECT 
[NameOfDonor] 
FROM [dbo].[_TEMPENDOWED] AS ENDF
WHERE [ENDF].[NameOfDonor] NOT IN (SELECT [DONORNAME] FROM [dbo].[DONORINFO])

donorid迭代将是这样的两个不同的表源（由于机密性，我已经省略了捐赠者名称）。

DONORID DONORNAME (from _TEMPENDOWMENTFUND)
------------------------
DN00000001  test
DN00000002  test
DN00000003  test
DN00000004  test
DN00000005  test
DN00000006  test
DN00000007  test

DONORID DONORNAME (from _TEMPENDOWED)
------------------------
DN00000007  test
DN00000008  test
DN00000009  test
DN00000010  test
DN00000011  test
DN00000012  test
DN00000013  test

插入具有唯一ID的记录时，无法在触发器上执行多行插入

2 个答案: