Question

accounts table
----------------

id  name
10  ABC Company     
11  XYZ Company 
12  LMN Company 
13  EFG Company 
14  JKL Company 
..  ...........
..  ...........

accounts_opportunities table
-----------------------
id  opportunity_id    account_id    deleted
1   1         11        0
2   2         11        0
3   3         12        0
4   4         12        0
5   5         13        0
6   6         14        0
.   .         ..        .
.   .         ..        .


opportunities table
-----------------
id  name    amount
1   Opp 1   100
2   Opp 2   50
3   Opp 3   500
4   Opp 4   600
5   Opp 5   200
6   Opp 6   1000

我正在尝试从上表中选择前20个帐户。我写了以下查询即，

SELECT TOP 20 COUNT(*) as number_of_opportunities, 
    (
        SELECT accounts.name  
        FROM accounts 
        WHERE accounts.id=accounts_opportunities.account_id
    ) as account_name
FROM accounts_opportunities 
JOIN opportunities ON opportunities.id = accounts_opportunities.opportunity_id 
WHERE accounts_opportunities.deleted != '1'   
GROUP BY accounts_opportunities.account_id
ORDER BY number_of_opportunities DESC

以上查询提供以下输出;

Account name    Number of Opportunities
------------    -----------------------
ABC Company     3 

XYZ Company     2 
LMN Company     2

EFG Company     1
JKL Company     1

XYZ和LMN具有相同的数字机会，但如果我计算XYZ的总数量机会小于LMN总数量。此外，JKL的数量高于EFG。

我的问题是如何从 number_of_opportunities 然后总机会金额订购此查询。有人可以给我一个指南..

预期输出

Account name    Number of Opportunities
------------    -----------------------
ABC Company     3 
LMN Company     2
EFG Company     1
JKL Company     1
XYZ Company     2

Answer 1

试试这个：

SELECT TOP 20 a.name, COUNT(*) AS [Number of Opportunities]
FROM accounts AS a
INNER JOIN accounts_opportunities AS ao ON a.id = ao.account_id
INNER JOIN opportunities AS o ON o.id = ao.opportunity_id 
WHERE ao.deleted != 1
GROUP BY a.id, a.name   
ORDER BY COUNT(*) DESC, SUM(amount) DESC

因此，您可以使用SUM(amount)在ORDER BY子句中添加DESC。如果COUNT(*)出现问题，我们会在其他帐户中添加金额较高的帐户。

如何使用两列来排序SQL Query？

1 个答案: