Question

我有这三个表

ITEM 表：

 ITEM_ID    AMOUNT_DUE SERVICE_CHARGE
 -----------------------------------
 1          1000        100

投标表：

 ITEM_ID    TYPE_ID  AMOUNT
 -------------------------------
 1          0        600
 1          1        500

TYPE 表格：

 TYPE_ID    TYPE_NAME
 -------------------------------
 0          CASH
 1          CREDIT

我试过了：

select 
    TYPE_NAME, 
    sum(AMOUNT) as Amount, 
    sum(ServiceCharge) as SC 
from 
    TENDER 
left join
    TYPE on TYPE.TYPE_ID = TENDER.TYPE_ID
left join 
    ITEM on ITEM.ITEM_ID = TENDER.ITEM_ID
group by 
    TYPE_NAME

但服务费用的结果已经重复，如

 TYPE_NAME    AMOUNT  SC
 -------------------------------
 CASH         650     100
 CREDIT       500     100

注意：服务费用计算为* 10

Answer 1

可能是这样的：

select TYPE_NAME, sum(AMOUNT) as Amount, 
sum(ServiceCharge)/ (COUNT(*) OVER (PARTITION BY TENDER.ITEM_ID) ) as SC 
from TENDER 
LEFT JOIN TYPE ON TYPE.TYPE_ID = TENDER.TYPE_ID
LEFT JOIN ITEM ON ITEM.ITEM_ID = TENDER.ITEM_ID
GROUP BY TYPE_NAME, TENDER.ITEM_ID;

Answer 2

由于service charge是amount的10％，因此您不需要join到item表。相反，只需将sum(amount)乘以.1：

select TYPE_NAME, sum(AMOUNT) as Amount, sum(AMOUNT) * .1 as SC
from TENDER 
    LEFT JOIN TYPE ON TYPE.TYPE_ID = TENDER.TYPE_ID
GROUP BY TYPE_NAME

SQL Fiddle Demo

导致：

type_name   Amount  SC
Cash        600     60
Credit      500     50

Answer 3

我怀疑你想要这个：

select ITEM.ITEM_ID, ServiceCharge,
       SUM(CASE WHEN TYPE_NAME = 'CASH' THEN Amount END) as Cash,
       SUM(CASE WHEN TYPE_NAME = 'CREDIT' THEN Amount END) as Credit
from TENDER LEFT JOIN
     TYPE
     ON TYPE.TYPE_ID = TENDER.TYPE_ID LEFT JOIN
     ITEM
     ON ITEM.ITEM_ID = TENDER.ITEM_ID
GROUP BY ITEM.ITEM_ID, ServiceCharge;

这会将值放入列中，因此不会重复。

Answer 4

我结合了Slava Murygin和sandeep rawat的答案，这给了我成功的销售成果。

想出了这个

 ;WITH SUMS AS (
 select TYPE_NAME, AMOUNT as Amount, 
 sum(ServiceCharge)/ (COUNT(*) OVER (PARTITION BY TENDER.ITEM_ID) ) as SC 
 from TENDER 
 LEFT JOIN TYPE ON TYPE.TYPE_ID = TENDER.TYPE_ID
 LEFT JOIN ITEM ON ITEM.ITEM_ID = TENDER.ITEM_ID
 GROUP BY TYPE_NAME, TENDER.ITEM_ID, AMOUNT
 )
 Select Type_Name , Amount, Tender.ITEM_ID
 From Sums
 Group by TYPE_NAME

谢谢！

Answer 5

这对你有用吗？请根据您的方便更改列名称

SELECT 
    tender.item,typename,SUM(amount)as amount, SUM(Service_Charge/cntItem) as servercharge
FROM 
    woddb.TENDER_Table as Tender 
INNER JOIN 
    (SELECT item, count(item) as cntItem FROM woddb.Tender_Table GROUP BY ITEM) as cntTable
ON 
    Tender.item = cntTable.Item
LEFT JOIN
    woddb.TYPE_Table  as TYPETable 
ON 
    TYPETable.TYPEID = Tender.TYPEID
LEFT JOIN 
    woddb.ITEM_table as ITEMtable 
ON 
    ITEMtable.ITEM = Tender.ITEM
GROUP BY 
    tender.item,typename

SQL查询：如何删除重复的服务费？

5 个答案: