Question

我支持以下脚本参数。我希望在传递并发出错误时找出重复的参数。你能帮我么。

#! /bin/sh
VCFile=
gCFFile=
PW=xyzzy

while test $# -gt 0 
do
  option=$(echo $1 | tr a-z A-Z)
  case $option in

(-VO)    shift
          VCfile=$1
          ;;
(-CON)  shift
          gCFFile=$1
          ;;
(-PASSWORD) shift
          PW=$1
          ;;
(*)     
          print "\nerror -The command line argument $1 is invalid\n"
          print "Testscript has aborted.\n"
          exit 2  
          ;;
   esac
   shift
done

./Install.sh -VO abc.txt -CON tt.txt - pass
./Install.sh -VO abc.txt -CON tt.txt -ss

error -The command line argument -ss is invalid
Testscript has aborted.

如果使用下面的重复参数

运行

./Install.sh -VO abc.txt -CON tt.txt -CON ta.txt -PASSWORD ABC -PASSWORD non

- 没有失败，这里我想在输入重复选项时抛出错误。

Answer 1

只需检查是否已设置该值。

#!/bin/sh
unset VCFile
unset gCFFile
unset PW  # set default below

die() { echo "$@"; exit 1; } >&2
while test $# -gt 0 
do
  option=$(echo $1 | tr a-z A-Z)
  case $option in

(-VO)    shift
          test "${VCFile+set}" = set && die -VO set twice
          VCfile=$1
          ;;
(-CON)  shift
          test "${gCFFile+set}" = set && die -CON given twice
          gCFFile=$1
          ;;
(-PASSWORD) shift
          test "${PW+set}" = set && die -PASSWORD given twice
          PW=$1
          ;;
(*)     
          die "error -The command line argument $1 is invalid
          ;;
   esac
   shift
done
: ${PW=xyzzy}  # if -PASSWORD was not given, set a default

Answer 2

您可以在while循环之前使用以下代码。

if [ `echo "$@" | grep -o "\-CON" | wc -l` -gt 0 ] || [ `echo "$@" | grep -o "\-PASSWORD" | wc -l` -gt 0 ] ||  [ `echo "$@" | grep -o "\-VO" | wc -l` -gt 0 ]
then
echo "  Duplicate set of parameter is passed. $# is invalid\n"
echo "Testscript has aborted.\n"
exit 0
fi

或者你可以添加case语句来获取哪个参数是重复的。

while  test $# -gt 0
do
  option=$(echo $1 | tr a-z A-Z)
  case $option in

(-VO)    shift
          VCfile=$1
          if  [ `echo "$@" | grep -o "\-VO" | wc -l` -gt 0 ]
          then
             echo "Duplicate set of parameter is passed for -VO . Parameters passed are invalid\n"
             echo "Testscript has aborted.\n"
          exit 0
          fi
          ;;
(-CON)  shift
          gCFFile=$1;
          if  [ `echo "$@" | grep -o "\-CON" | wc -l` -gt 0 ]
          then
             echo "Duplicate set of parameter is passed for -CON . Parameters passed are invalid\n"
             echo "Testscript has aborted.\n"
          exit 0
          fi
          ;;
(-PASSWORD) shift
          PW=$1
          if  [ `echo "$@" | grep -o "\-PASSWORD" | wc -l` -gt 0 ]
          then
             echo "Duplicate set of parameter is passed for -PASSWORD . Parameters passed are invalid\n"
             echo "Testscript has aborted.\n"
          exit 0
          fi
          ;;
(*)
          echo "\nerror -The command line argument $1 is invalid\n"
          echo "Testscript has aborted.\n"
          exit 2
          ;;
   esac
   shift
done

让我知道它是否有效。

如何在shell脚本中找出重复的参数

2 个答案: