我不知道为什么我搜索SQLite数据库并返回游标的方法返回null。我已经从txt文件加载了数据库,并且在尝试在应用程序中实现搜索功能时,我试图查询同一个数据库以返回可能匹配的列表。但是,当我追溯错误时,我意识到这个方法不断返回null而不是我想要的游标。谁能帮我这个?我很高兴地承认我对此非常陌生,并希望得到任何帮助。
这是我的数据库表,方法getWordMatches()
返回null:
public class DatabaseTable {
public static final String TAG = "ConstantDatabase";
//the columns included in the table
public static final String COL_QUANTITY = "QUANTIY";
public static final String COL_VALUE = "VALUE";
public static final String COL_UNCERTAINTY = "UNCERTAINTY";
public static final String COL_UNIT = "UNIT";
public static final String _id = "_id";
private static final String DATABASE_NAME = "CONSTANTS";
private static final String FTS_VIRTUAL_TABLE = "FTS";
private static final int DATABASE_VERSION = 1;
private final DatabaseOpenHelper mDatabaseOpenHelper;
public DatabaseTable(Context context){
mDatabaseOpenHelper = new DatabaseOpenHelper(context);
}
private static class DatabaseOpenHelper extends SQLiteOpenHelper {
private final Context mHelperContext;
private SQLiteDatabase mDatabase;
private static final String FTS_TABLE_CREATE =
"CREATE VIRTUAL TABLE " + FTS_VIRTUAL_TABLE +
" USING fts3 (" +_id+ ", "+
COL_QUANTITY + ", " +
COL_VALUE + "," +
COL_UNCERTAINTY + "," +
COL_UNIT + ")";
public DatabaseOpenHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
Log.e("Database Operation", "DatabaseOpenHelper constructor called");
mHelperContext = context;
}
@Override
public void onCreate(SQLiteDatabase db) {
mDatabase = db;
mDatabase.execSQL(FTS_TABLE_CREATE);
Log.e("Database Operation", "Constants Table Created ...");
loadConstants();
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
Log.w(TAG, "Upgrading database from version " + oldVersion + " to "
+ newVersion + ", which will destroy all old data");
db.execSQL("DROP TABLE IF EXISTS " + FTS_VIRTUAL_TABLE);
onCreate(db);
}
public SQLiteDatabase getmDatabase(){
return mDatabase;
}
// populating the virtual table with a string reading code
private void loadConstants() {
new Thread(new Runnable() {
public void run() {
try {
loadConstantss();
} catch (IOException e) {
throw new RuntimeException(e);
}
}
}).start();
Log.e("Loading", "Constants Table Populated ...");
}
private void loadConstantss() throws IOException {
final Resources resources = mHelperContext.getResources();
InputStream inputStream = resources.openRawResource(R.raw.txt);
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
try {
String line;
while ((line = reader.readLine()) != null) {
String[] strings = TextUtils.split(line, ",");
if (strings.length < 4) continue;
long id = addConstant(strings[0].trim(), strings[1].trim(), strings[2].trim(), strings[3].trim());
if (id < 0) {
Log.e(TAG, "unable to add word: " + strings[0].trim());
}
}
} finally {
reader.close();
}
}
public long addConstant(String quantity, String value, String uncertainty, String unit) {
ContentValues initialValues = new ContentValues();
initialValues.put(COL_QUANTITY, quantity);
initialValues.put(COL_VALUE, value);
initialValues.put(COL_UNCERTAINTY, uncertainty);
initialValues.put(COL_UNIT, unit);
return mDatabase.insert(FTS_VIRTUAL_TABLE, null, initialValues);
}
//database openhelper ends
}
public Cursor getWordMatches(String query, String[] columns) {
String selection = COL_QUANTITY + " MATCH ?";
String[] selectionArgs = new String[] {query+"*"};
return query(selection, selectionArgs, columns);
}
public Cursor query(String selection, String[] selectionArgs, String[] columns) {
SQLiteQueryBuilder builder = new SQLiteQueryBuilder();
builder.setTables(FTS_VIRTUAL_TABLE);
Cursor cursor = builder.query(mDatabaseOpenHelper.getReadableDatabase(),
columns, selection, selectionArgs, null, null, null);
if (cursor == null) {
return null;
} else if (!cursor.moveToFirst()) {
cursor.close();
return null;
}
return cursor;
}
public Cursor getAllTitles()
{
return mDatabaseOpenHelper.getmDatabase().query(FTS_VIRTUAL_TABLE, new String[] {
COL_QUANTITY,
COL_UNCERTAINTY,
COL_UNIT,
COL_VALUE},
null,
null,
null,
null,
null);
}
}
再次,非常感谢你。
编辑:
导致我这样做的原始错误是当在另一个活动中调用它时:
Cursor c=db.getWordMatches(query,colums);
Log.e("cursor returned",c.toString());
log cat返回
java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String java.lang.Object.toString()' on a null object reference
答案 0 :(得分:2)
如果光标中没有数据,您的代码会关闭光标
if (cursor == null) {
return null;
} else if (!cursor.moveToFirst()) {
cursor.close();
return null;
}
这样做会在常见用例中为您提供空值。然后你使用光标而不检查
Log.e("cursor returned", c.toString());
如果这是您取消选中光标的唯一地方,您只需将其替换为
即可Log.e("cursor returned", String.valueOf(c));
否则您可能需要改进实施。无论如何,你可能需要查看DatabaseUtils
。