我正在编写一个基本的聊天程序。这样做的目的是首先通过启动server.py脚本来设置服务器,然后让它在后台运行。然后,用户启动client.py脚本并选择一个名称,然后开始键入消息并发送它。问题是当我尝试发送它时会返回此错误。
Traceback (most recent call last):
File "C:\Users\Hello\AppData\Local\Programs\Python\Python35-32\client.py", line 38, in <module>
s.sendto(alias + ': ' + message.encode() , server)
TypeError: Can't convert 'bytes' object to str implicitly
这是server.py脚本---
import socket
import time
host = '127.0.0.1'
port = 47015
clients = []
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind((host, port))
s.setblocking(0)
qutting = False
print("Server Started")
while not qutting:
try:
data, addr = s.recvfrom(1024)
if 'Quit' in str(data):
qutting = True
if addr not in clients:
clients.append(addr)
print(time.ctime(time.time()) + str(addr) + ": :" + str(data))
for client in clients:
s.sendto(data, client)
except:
pass
s.close()
然后是client.py脚本----
import socket
import threading
import time
tLock = threading.Lock()
shutdown = False
def recieving(name, sock):
while not shutdown:
try:
tLock.acquire()
while True:
data, addr = sock.recvfrom(1024)
data.decode()
print(str(data))
except:
pass
finally:
tLock.release()
host = '127.0.0.1'
port = 0
server = ("127.0.0.1", 47015)
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind((host, port))
s.setblocking(0)
rT = threading.Thread(target=recieving, args=('RecvThread', s))
rT.start()
alias = input("Name: ")
message = input(alias + "->")
while message != 'q':
if message != '':
s.sendto(alias + ': ' + message.encode() , server)
tLock.acquire()
message = input(alias + '->')
tLock.release()
time.sleep(0.2)
shutdown = True
rT.join()
s.close()
因此,如果你有任何想法如何解决这个问题,那么一个侧面的问题是,是否会有一种方法可以使接收线程一直运行以便主动更新聊天?
答案 0 :(得分:0)
问题出在这一行:
s.sendto(alias + ': ' + message.encode() , server)
您正在将message
转换为bytes
,但之后您将未转换的字符串添加到bytes
对象。这是一个无效的操作,正如错误消息告诉您的那样,因为bytes
无法明确地转换为字符串。尝试编码整个事情:
s.sendto((alias + ': ' + message).encode() , server)