Question

说我有这样的数组：

$chartData = array ( [00] => 1 [03] => 1 [09] => 1 [10] => 3 [11] => 1 [12] => 4 [13] => 2 [14] => 4 [15] => 6 [16] => 3 [17] => 5 [18] => 2 [20] => 1 [22] => 1 ) 1

如何填写缺失的索引直至24（02,04,05，等等，直到24）0？

Answer 1

您可以尝试这样的事情

function addkeyforArray(&$array)
{
    end($array);
    $maxcount = key($array); //Get the final key as max!
    for($i = 01; $i < $maxcount; $i++)
    {
        if(!isset($array[$i]))
        {
            $array[$i] = '';
        }
    }
}

addkeyforArray($array);

Answer 2

最简单的方法是双线循环。

for ($i = min($k=array_keys($chartData)); $i<=max($k); $i++) 
    $chartData[$i] = isset($chartData[$i]) ? $chartData[$i] : 0;

Answer 3

我会得到键列表，使用它来创建期望的键列表，然后在数组上执行diff。就这样

//Get the keys
$keys = array_keys($chartData);

//Convert them to integers for easier use
$keys = array_map(function ($key) {
    return (int) $key;
}, $keys);

//Get the last key
end($keys);
$lastKey = current($keys);

//Create the keys that we expect
$expectedKeys = range(0, $lastKey);

//Find out which keys are missing
$missingKeys = array_diff($expectedKeys, $keys);

填写php中缺少的数组索引

3 个答案: