我在Unity3D中使用ScrollView,Texts和Buttons制作了列表。 当用户单击项目附近的按钮时 - 应删除该项目。 使用Instantiate方法创建按钮和文本。 项目列表是通用列表(列表)。
项目清单:
public List<Item> Items { get; set; }
创建按钮和文字:
public Button itemButton;
public Text itemText;
(...)
public void ShowItems()
{
ClearItems(); //Destroys button and text gameObjects.
foreach (var item in Globals.Items)
{
var text = Instantiate(itemText) as Text;
var button = Instantiate(itemButton) as Button;
button.GetComponentInChildren<Text>().text = "Delete";
textsList.Add(text); //save Text element to list to have possibility of destroying Text gameObjects
buttonsList.Add(button);//save Button element to list to have possibility of destroying Button gameObjects
text.gameObject.SetActive(true);
button.gameObject.SetActive(true);
//(...) Setting GUI items position here
}
}
如何检测单击哪个项目的按钮以删除该项目?
我不知道如何获得第二个按钮==第二个项目删除。
答案 0 :(得分:3)
只需添加一行代码:
foreach (var item in Globals.Items)
{
var text = Instantiate(itemText) as Text;
var button = Instantiate(itemButton) as Button;
button.GetComponentInChildren<Text>().text = "Delete";
textsList.Add(text); //save Text element to list to have possibility of destroying Text gameObjects
buttonsList.Add(button);//save Button element to list to have possibility of destroying Button gameObjects
text.gameObject.SetActive(true);
button.gameObject.SetActive(true);
// this line:
button.onClick.AddListener(delegate {Destroy(text.gameObject); Destroy(button.gameObject);});
//(...) Setting GUI items position here
}