我正在尝试订阅从Observable
创建的Subject
,每当我订阅没有错误处理程序时,我都会收到错误this._subscribe is not a function
。我发现this问题描述了类似的错误;但答案似乎不适合我的情况。这是我的代码:
const subject = new Rx.Subject();
subject
.withLatestFrom(otherObservable)
.subscribe(
values => {
// some logic
}
);
我也尝试过:
const subject = new Rx.Subject();
subject
.withLatestFrom(otherObservable)
.subscribeOnNext(
values => {
// some logic
}
);
我得到同样的错误。当我尝试subscribe
时,这是堆栈跟踪:
Observable.Rx.Observable.observableProto.subscribe.observableProto.forEach (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2034:19)
WithLatestFromObservable.subscribeCore (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:4084:33)
WithLatestFromObservable.tryCatcher (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:63:31)
setDisposable [as action] (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2082:46)
ScheduledItem.invokeCore (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:896:33)
ScheduledItem.invoke (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:884:40)
runTrampoline (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:1125:37)
tryCatcher (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:63:31)
CurrentThreadScheduler.schedule (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:1141:45)
WithLatestFromObservable.Rx.ObservableBase.ObservableBase._subscribe (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2095:32)
WithLatestFromObservable.Rx.Observable.observableProto.subscribe.observableProto.forEach (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2034:19)
这是我尝试subscribeOnNext
Observable.Rx.Observable.observableProto.subscribe.observableProto.forEach (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2034:19)
WithLatestFromObservable.subscribeCore (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:4084:33)
WithLatestFromObservable.tryCatcher (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:63:31)
setDisposable [as action] (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2082:46)
ScheduledItem.invokeCore (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:896:33)
ScheduledItem.invoke (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:884:40)
runTrampoline (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:1125:37)
tryCatcher (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:63:31)
CurrentThreadScheduler.schedule (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:1141:45)
WithLatestFromObservable.Rx.ObservableBase.ObservableBase._subscribe (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2095:32)
WithLatestFromObservable.Rx.Observable.observableProto.subscribeOnNext (/home/ryan/code/redurx/node_modules/rx/dist/rx.js:2046:19)
如果我将() => null
之类的简单错误处理程序传递给subscribe
,我就不会收到错误。有什么想法吗?
答案 0 :(得分:0)
感谢user3743222 我明白了。事实证明(实际上逻辑上)您无法订阅普通的可观察对象。它需要以一种值得观察的方式构建。我将单元测试中otherObservable
的初始化从new Rx.Observable()
更改为Rx.Observable.just(1)
,现在可以订阅。我有点困惑,但是当我通过onNext
和onError
处理程序时,为什么它没有抛出同样的错误。但我会接受它。