我想将我的DataFrame写入CSV文件。结果如下所示。行彼此不对齐。你有什么建议可以解决这个问题吗?
代码:
max_by
file.csv的内容:
++++++++++++++++++++++++ C1 c2 c3 c2 1 1.111 1.111 1.111 2 23.261 1.111 1.111 3 138.383 1.111 1.111 2 228.717 1.111 1.111 5 358.225 1.111 1.111 6 268.173 1.111 1.111 7 577.311 1.111 1.111 8 687.623 1.111 1.111 3 737.357 1.111 1.111 11 317.185 1.111 1.111 11 1116.813 1.111 1.111 12 1126.521 1.111 1.111 13 1151.325 1.111 1.111 22 2273.853 1.111 1.111 23 2583.581 1.111 1.111 22 2618.822 1.111 1.111 25 1.111 1.111 23.261 26 23.261 1.111 23.261 27 138.383 1.111 23.261 28 228.717 1.111 23.261 23 358.225 1.111 23.261
答案 0 :(得分:3)
csv文件不应该以这种方式垂直对齐。它们应该用逗号分隔值。你似乎想要格式很好的ascii。
print dataframe.__repr__()
C1 c2 c3 c2.1
0 1 1.111 1.111 1.111
1 2 23.261 1.111 1.111
2 3 138.383 1.111 1.111
3 2 228.717 1.111 1.111
4 5 358.225 1.111 1.111
5 6 268.173 1.111 1.111
6 7 577.311 1.111 1.111
7 8 687.623 1.111 1.111
8 3 737.357 1.111 1.111
9 11 317.185 1.111 1.111
10 11 1116.813 1.111 1.111
11 12 1126.521 1.111 1.111
12 13 1151.325 1.111 1.111
13 22 2273.853 1.111 1.111
14 23 2583.581 1.111 1.111
15 22 2618.822 1.111 1.111
16 25 1.111 1.111 23.261
17 26 23.261 1.111 23.261
18 27 138.383 1.111 23.261
19 28 228.717 1.111 23.261
20 23 358.225 1.111 23.261
或:
with open('./filename.txt', 'w') as fo:
fo.write(dataframe.__repr__())
答案 1 :(得分:0)
使用分隔符标签:
dataframe.to_csv(data,sep="\t",index=False,header=False,encoding='ascii',
float_format='%10.4f',quoting=csv.QUOTE_NONE, escapechar=" ", mode='a+')
答案 2 :(得分:0)
This can be done by fixing the number of digits and the width of column headers.
Here is how one can fix number of characters in column headers. (Here it is fixed to 10)
for name in df.columns:
df.rename(columns={name: "{:10}".format(name)}, inplace=True)
Specify the format of numbers while writing csv file.
df.to_csv(<path>, float_format='%0.4e')
The only problem with this approach is, it is not possible to specify different formats for different columns.