Question

正如标题所说。简单的if语句在Bash中。我一直试图弄清楚为什么这个循环不起作用，我现在还没有拿出任何东西两天。洞察力将不胜感激。

declare -r TIMESTAMP=$(date "+%Y-%m-%d %H:%M:%S,%3N")

CHECK="$(grep -c "$TIMESTAMP" /var/log/host/logname.log)"
if [ "$CHECK" -eq 0 ]
then
     COLOR="green"
elif [ 0 -lt "$CHECK" ] && [ "$CHECK" -le 5 ]
     COLOR="yellow"
else
     COLOR="red"
fi

COLOR var是由我使用的系统预设的。红色/黄色/绿色都是正确的，我的语法或逻辑都是问题，尽管我一直在努力确定哪个。谢谢！

编辑：我的错误。清晨和问题充斥着错别字。我修好了他们。错误如下，

syntax error near unexpected token `else'
`     else'

Answer 1

你忘记了引用，然后是。

declare -r TIMESTAMP=$(date "+%Y-%m-%d %H:%M:%S,%3N")   # missing " here

CHECK="$(grep -c "$TIMESTAMP" /var/log/host/logname.log)"
if [ "$CHECK" -eq 0 ]; then
     COLOR="green"
elif [ 0 -lt "$CHECK" ] && [ "$CHECK" -le 5 ]; then    # missing then was here
     COLOR="yellow"
else
     COLOR="red"
fi

Answer 2

您有一些错误，这可能会有所帮助

declare -r TIMESTAMP=$(date "+%Y-%m-%d %H:%M:%S,%3N")
CHECK="$(grep -c "$TIMESTAMP" /var/log/host/logname.log)"
if [ "$CHECK" -eq 0 ]
then
   COLOR="green"
elif [ 0 -lt "$CHECK" ] && [ "$CHECK" -le 5 ]
then
   COLOR="yellow"
else
   COLOR="green"
fi

Bash if / else Loop Error

2 个答案: