Question

您好我是iOS开发的新手。我想从默认联系人应用中选择一个联系人。为此，我创建了一个应用程序，允许用户从iPhone默认联系人应用程序中选择一个联系人。对于iOS 9+版本，我使用以下剪辑。

- (IBAction)btnAction:(id)sender {

    CNContactPickerViewController *contactPicker = [[CNContactPickerViewController alloc] init];

    contactPicker.delegate = self;
    contactPicker.displayedPropertyKeys = (NSArray *)CNContactGivenNameKey;

    [self presentViewController:picker animated:YES completion:nil];
}

-(void) contactPicker:(CNContactPickerViewController *)picker didSelectContact:(CNContact *)contact{
    NSLog(@"Contact : %@",contact);
}

-(void)contactPickerDidCancel:(CNContactPickerViewController *)picker {
    NSLog(@"Cancelled");
}

我还在我的uiviewcontroller中添加了CNContactPickerDelegate委托。当我执行上面的代码时，它会打开联系人应用程序，但是当点击一个联系人时，该应用程序将变为空白。

提前致谢，任何人都可以分享您的知识，在Objective-C中使用CNContactPickerViewController。

Answer 1

问题是由此代码引起的：

contactPicker.displayedPropertyKeys = (NSArray *)CNContactGivenNameKey;

displayedPropertyKeys期望NSArray包含NSString个值。在您的代码中，您尝试将NSString类型转换为NSArray并将其设置为此属性的值。

您需要将代码更改为：

contactPicker.displayedPropertyKeys = @[CNContactGivenNameKey];

Answer 2

#pragma mark - CNContactPickerViewController Delegate method implementation
(void)contactPicker:(CNContactPickerViewController *)picker didSelectContact:(CNContact *)contact
{
    NSMutableArray *contactNumberArray = [[NSMutableArray alloc]init];
    selectedName=[NSString stringWithFormat:@"%@",contact.givenName];
    NSLog(@"%@",selectedName);
    NSString *tempString = [NSString stringWithFormat:@"name : %@ %@ %@\n",contact.givenName, contact.familyName, contact.organizationName];
    //    // 1.  (Phone Numbers)
        tempString = [NSString stringWithFormat:@"%@phoneNumbers : ",tempString];
       // NSArray*phoneNumber = contact.phoneNumbers;
        for (CNLabeledValue *phoneNumber in contact.phoneNumbers)
        {
          CNPhoneNumber *phone = phoneNumber.value;
            tempString = [NSString stringWithFormat:@"%@<%@>",tempString,phone.stringValue];
             [contactNumberArray addObject:phone];
            selectedPhNumber=[[NSString stringWithFormat:@"%@",phone.stringValue] stringByReplacingOccurrencesOfString:@" " withString:@""];
             NSLog(@"%@",selectedPhNumber);
        }

         //2.  (Emails)
        tempString = [NSString stringWithFormat:@"%@\n Email : ",tempString];
        for (CNLabeledValue *email in contact.emailAddresses)
        {
            selectedEmail=[NSString stringWithFormat:@"%@", email.value];
            tempString = [NSString stringWithFormat:@"%@<%@>",tempString,email.value];
               [contactNumberArray addObject:email];
             NSLog(@"%@",selectedEmail);
        }
 [self sendRefferelDetailsToServer];

}

Answer 3

-(void)contactPicker:(CNContactPickerViewController *)picker didSelectContacts:(NSArray<CNContact *> *)contacts{

    NSLog(@" %@",contacts);

    CNContact *contact=[contacts objectAtIndex:0];

    NSLog(@"name = %@",contact.givenName);


}

[1]：https://i.stack.imgur.com/9Sp1G.png使用上面的代码从多个选项中获取给定名称，

Answer 4

评论以下一行，然后重试。

{{1}}

如何使用CNContactPickerViewController与目标c？

4 个答案: