在Python中对嵌套字典进行排序

时间:2016-06-29 09:16:53

标签: python sorting dictionary hashtable

我有以下字典。

var = a = { 
  'Black': { 'grams': 1906, 'price': 2.05},
  'Blue': { 'grams': 9526, 'price': 22.88},
  'Gold': { 'grams': 194, 'price': 8.24},
  'Magenta': { 'grams': 6035, 'price': 56.69},
  'Maroon': { 'grams': 922, 'price': 18.76},
  'Mint green': { 'grams': 9961, 'price': 63.89},
  'Orchid': { 'grams': 4970, 'price': 10.78},
  'Tan': { 'grams': 6738, 'price': 50.54},
  'Yellow': { 'grams': 6045, 'price': 54.19}
}

如何根据price对其进行排序。因此,生成的字典将如下所示。

result = { 
  'Black': { 'grams': 1906, 'price': 2.05},
  'Gold': { 'grams': 194, 'price': 8.24},
  'Orchid': { 'grams': 4970, 'price': 10.78},
  'Maroon': { 'grams': 922, 'price': 18.76},
  'Blue': { 'grams': 9526, 'price': 22.88},
  'Tan': { 'grams': 6738, 'price': 50.54},
  'Magenta': { 'grams': 6035, 'price': 56.69},
  'Mint green': { 'grams': 9961, 'price': 63.89}, 
}

4 个答案:

答案 0 :(得分:6)

从已订购商品元组列表构建OrderedDict

from collections import OrderedDict

ordered = OrderedDict(sorted(a.items(), key=lambda i: i[1]['price']))

.items()假定Python 3,在Python 2中iteritems也应该这样做。)

答案 1 :(得分:1)

for s in sorted(a.iteritems(), key=lambda (x, y): y['price']):
       print s

或通过OrderedDict

from collections import OrderedDict
res = OrderedDict(sorted(a.items(), key=lambda x: x[1]['price'], reverse=False))
print res

输出:

[('Black', {'price': 2.05, 'grams': 1906}), ('Gold', {'price': 8.24, 'grams': 194}), ('Orchid', {'price': 10.78, 'grams': 4970}), ('Maroon', {'price': 18.76, 'grams': 922}), ('Blue', {'price': 22.88, 'grams': 9526}), ('Tan', {'price': 50.54, 'grams': 6738}), ('Yellow', {'price': 54.19, 'grams': 6045}), ('Magenta', {'price': 56.69, 'grams': 6035}), ('Mint green', {'price': 63.89, 'grams': 9961})]

答案 2 :(得分:0)

import collections

update=collections.OrderedDict()
result = sorted(a, key=lambda x: (a[x]['price']))
for r in result:
    update[r]=a[r]

print(update)

答案 3 :(得分:0)

您还可以使用getitem库中的operator

from collections import OrderedDict
from operator import getitem

sorted_dict = OrderedDict(sorted(a.items(), key = lambda x:getitem(x[1],'price')))

print(sorted_dict)

输出:

OrderedDict([('Black', {'grams': 1906, 'price': 2.05}), ('Gold', {'grams': 194, 'price': 8.24}), ('Orchid', {'grams': 4970, 'price': 10.78}), ('Maroon', {'grams': 922, 'price': 18.76}), ('Blue', {'grams': 9526, 'price': 22.88}), ('Tan', {'grams': 6738, 'price': 50.54}), ('Yellow', {'grams': 6045, 'price': 54.19}), ('Magenta', {'grams': 6035, 'price': 56.69}), ('Mint green', {'grams': 9961, 'price': 63.89})])