是否有一种SQL方法来显示DB2 Z / OS中表或视图上的特权?我想实现这样的目标:
select * from sysibm.magic_table where table_name = 'users'
|TABLE_NAME|PRIVILEGE_TYPE|USER_OR_GROUP_NAME|
| USERS| INSERT| ANDI|
| USERS| SELECT| ADMINS|
这可能吗?
答案 0 :(得分:2)
此查询告知grantee
列中的用户/角色名称以及...auth
列中Y
=正确存在,G
=正确存在的各个已分配的权限并有权将其授予他人。
SELECT
grantee,
screator,
stname,
tcreator,
ttname,
updatecols,
alterauth,
deleteauth,
indexauth,
insertauth,
selectauth,
updateauth
FROM
SYSIBM.SYSTABAUTH
WHERE
TTNAME = 'MY_TABLE'
AND TCREATOR = 'MY_SCHEMA'
示例结果集:
|GRANTEE |SCREATOR |STNAME |TCREATOR |TTNAME |UPDATECOLS|ALTERAUTH|DELETEAUTH|INDEXAUTH|INSERTAUTH|SELECTAUTH|UPDATEAUTH|
============================================================================================================================
|MY_SCHEMA|MY_SCHEMA|MY_TABLE|MY_SCHEMA|MY_TABLE| | | G| | G| G| G|
|USER2 |MY_SCHEMA|MY_TABLE|MY_SCHEMA|MY_TABLE| | | Y| | Y| Y| Y|
|USER3 |MY_SCHEMA|MY_TABLE|MY_SCHEMA|MY_TABLE| | | Y| | Y| Y| Y|
|GROUP1 |MY_SCHEMA|MY_TABLE|MY_SCHEMA|MY_TABLE| | | Y| | Y| Y| Y|
|GROUP2 |MY_SCHEMA|MY_TABLE|MY_SCHEMA|MY_TABLE| | | Y| | Y| Y| Y|
|GROUP3 |MY_SCHEMA|MY_TABLE|MY_SCHEMA|MY_TABLE| | | | | | Y| |
|GROUP4 |MY_SCHEMA|MY_TABLE|MY_SCHEMA|MY_TABLE| | | Y| | Y| Y| Y|
IBM documentation of SYSIBM.SYSTABAUTH(感谢@mustaccio)