Question

我想打印120个型号列表并同时保留＆＃34; $＆＃34;。

我的脚本是：

#!/bin/sh
for i in {1..10};do
declare model="$"model$i
model_list=$(paste $model)
done
echo $model_list

运行后，

paste: $model1: No such file or directory
paste: $model2: No such file or directory
paste: $model3: No such file or directory
paste: $model4: No such file or directory
paste: $model5: No such file or directory
paste: $model6: No such file or directory
paste: $model7: No such file or directory
paste: $model8: No such file or directory
paste: $model9: No such file or directory
paste: $model10: No such file or directory

期望的输出：

$model1 $model2 $model3 $model4 $model5 $model6 $model7 $model8 $model9 $model10

Answer 1

您必须通过$（反斜杠美元符号）转义\$。

例如：

#!/bin/sh

for i in {1..10}; do
  declare model="\$"model$i

  model_list+=$(paste $model)
done
echo $model_list

您还可以缩短脚本：

#!/bin/sh

for i in {1..10}; do
  model_list+=$(paste "\$model${i}")
done

echo $model_list

使用标题为$model1 - $model5的5个文件进行测试：

File Contents:
$model1 - a b c d e f g
$model2 - 1 2 3 4 5 6 7 8 9 10
$model3 - I J K L M N O P
$model4 - 11 12 13 14 15 16 17 18 19 20
$model5 - q r s t u v w x y z

Output:
a b c d e f g1 2 3 4 5 6 7 8 9 10I J K L M N O P11 12 13 14 15 16 17 18 19 20q r s t u v w x y z

Answer 2

如果您对输出感兴趣而不是创建数组，则可以使用下面的代码

for i in {1..10};do
echo -n "\$model$i "
done
echo

或

for i in {1..10};do
echo -n '$model'$i' '
done
echo

或

for i in {1..10};do
model_list=$model_list" \$model$i"
done
echo $model_list

打印定义的变量并保留$

2 个答案: