我现在使用的是JavaScript,我希望将每个<li>
的循环设置为“有效”,从n°1到<li>
n°4再次开始,每次都是n°1秒。
我现在有这个代码:
HTML
<ul class="collection">
<li id="first" class="collection-item active">Desplazate hacia la pestaña <strong>HORARIOS</strong>.</li>
<li id="second" class="collection-item ">Ingresa tu N° de documento.</li>
<li id="third" class="collection-item ">Presiona el botón <strong>INGRESAR</strong>.</li>
<li id="four" class="collection-item "><strong>LISTO!</strong> Ahora puedes ver los horarios de la semana.</li>
</ul>
的JavaScript
$(document).ready(function(){
setInterval(animacion,3000);
function animacion(){
$currently_selected = $('li.active')
// Loop back to first sibling if on the last one.
if ($currently_selected.next().length = 0){
$next_selected = $currently_selected.siblings().first()
} else {
$next_selected = $currently_selected.next()
$currently_selected.removeClass('active')
$next_selected.addClass('active')
}
}
});
请帮助我!
答案 0 :(得分:0)
==
时使用===
或length
,因为=
将充当assignment operator
,并且始终会将其评估为true
< / LI>
分配else
变量$next_selected
块
$(document).ready(function() {
setInterval(animacion, 3000);
function animacion() {
$currently_selected = $('li.active');
if ($currently_selected.next().length == 0) {
$next_selected = $currently_selected.siblings().first();
} else {
$next_selected = $currently_selected.next();
}
$currently_selected.removeClass('active');
$next_selected.addClass('active');
}
});
&#13;
.active {
color: green;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<ul class="collection">
<li id="first" class="collection-item active">Desplazate hacia la pestaña <strong>HORARIOS</strong>.</li>
<li id="second" class="collection-item ">Ingresa tu N° de documento.</li>
<li id="third" class="collection-item ">Presiona el botón <strong>INGRESAR</strong>.</li>
<li id="four" class="collection-item "><strong>LISTO!</strong> Ahora puedes ver los horarios de la semana.</li>
</ul>
&#13;
答案 1 :(得分:0)
这是一种方法。
setInterval(function(){
var items = $('.collection li');
items.each(function(ind,val){
if($(this).hasClass('active')){
$(this).removeClass('active');
if(ind !== items.length - 1) {
items.eq(ind + 1).addClass('active');
return false;
}else{
items.eq(0).addClass('active');
return false;
}
}
});
},3000);