很抱歉,如果之前有人询问过。我有JSON结构,如:
{"data":[
{"Date":"03/04/2016","Key":"A","Values":"123"},
{"Date":"04/04/2016","Key":"A","Values":"456"},
{"Date":"03/04/2016","Key":"B","Values":"789"},
{"Date":"04/04/2016","Key":"B","Values":"012"}
]}
我想将其更改为其他格式,该格式基本上按键分组,并将值的其余部分组合在一起
{"Result":[
{
"Key":"A"
"Values":[["03/04/2016","123"], ["04/04/2016","456"]]
},
{"Key":"B"
"Values":[["03/04/2016","789"]},["04/04/2016","012"]]
}
]}
我想这样做javascript / html
答案 0 :(得分:0)
如果不存在,您可以迭代并构建一个新对象。
var object = { "data": [{ "Date": "03/04/2016", "Key": "A", "Values": "123" }, { "Date": "04/04/2016", "Key": "A", "Values": "456" }, { "Date": "03/04/2016", "Key": "B", "Values": "789" }, { "Date": "04/04/2016", "Key": "B", "Values": "012" }], result: [] };
object.data.forEach(function (a) {
if (!this[a.Key]) {
this[a.Key] = { Key: a.Key, Values: [] };
object.result.push(this[a.Key]);
}
this[a.Key].Values.push([a.Date, a.Values]);
}, Object.create(null));
console.log(object);

答案 1 :(得分:0)
我认为这可以是一个更好的答案(但Nina的答案是您的问题条款的匹配)如果数据数据项具有不同的属性而您不想更改输入数据。
var raw = {"data":[
{"Date":"03/04/2016","Key":"A","Values":"123"},
{"Date":"04/04/2016","Key":"A","Values":"456"},
{"Date":"03/04/2016","Key":"B","Values":"789"},
{"Date":"04/04/2016","Key":"B","Values":"012"}
]};
var result = new Map;
raw.data.forEach(entry => {
var key = entry.Key;
if (this[key])
return this[key].push(getClonedData(entry));
this[key] = [getClonedData(entry)];
result.set(key, {
Key: key,
Values: this[key]
})
}, Object.create(null));
var filtered = {
result: [...result.values()]
}
console.log(filtered);
function getClonedData(entry) {
data = Object.assign({}, entry);
delete data.Key;
return data;
}