我有一张数据表如下:
cat score
a 80
c 88
b 36
b 96
d 99
b 76
d 89
a 50
d 69
b 36
d 59
b 96
b 86
c 98
a 50
a 90
c 83
b 66
如何使用SQL获取每只猫的最多3分?
答案 0 :(得分:2)
您可以使用变量:
SELECT cat, score
FROM (
SELECT cat, score,
@seq := IF(@c = cat, @seq + 1,
IF(@c := cat, 1, 1)) AS seq
FROM mytable
CROSS JOIN (SELECT @c := '', @seq := 0) x
ORDER BY cat, score DESC ) AS t
WHERE seq <= 3
答案 1 :(得分:1)
您可以使用union
(select cat, score
from my_table
where cat='a'
order by score desc
limit 3)
union
(select cat, score
from my_table
where cat='b'
order by score desc
limit 3)
union
(select cat, score
from my_table
where cat='c'
order by score desc
limit 3)
union
(select cat, score
from my_table
where cat='d'
order by score desc
limit 3)
答案 2 :(得分:1)
您可以使用相关查询来执行此操作:
SELECT tt.cat,tt.score FROM (
SELECT t.cat,t.score,
(SELECT COUNT(*) FROM YourTable s FROM YourTable s
WHERE s.cat = t.cat and t.score <= s.score) as cnt
FROM YourTable t) tt
WHERE tt.cnt < 4