我的下面的python代码出了什么问题?
我想连接到我的数据库,选择一些信息。这些是在列表的列表中,我抓住了列表,我做了一个" select..from..where..IN" :
import pypyodbc
connection = pypyodbc.connect('Driver={SQL Server};'
'Server=X;'
'Database=Y;'
'uid=X;pwd=Y')
cursor = connection.cursor()
NbFiche=0
L=[[4702, 3095, 3543], [2040, 2030, 2020], []]
for i in range(0,3):
log=L[i]
if (log is not None):
if (len(log)==3):
SQLCommand = ("select count(*) from PRODUCTION where ID_TV IN (?) ")
cursor.execute(SQLCommand,(log,))
results = cursor.fetchone()
NbFiche += results[0]
这是错误:
Traceback (most recent call last):
File "//Srvaktct-bur02/telecontact/TCT TRAVAIL/Pôle Fichier/AMIRA/STATISTIQUES/nimp.py", line 18, in <module>
cursor.execute(SQLCommand,(log,))
File "C:\Users\admin_fichier\AppData\Local\Programs\Python\Python35\lib\site-packages\pypyodbc-1.3.3-py3.5.egg\pypyodbc.py", line 1470, in execute
self._BindParams(param_types)
File "C:\Users\admin_fichier\AppData\Local\Programs\Python\Python35\lib\site-packages\pypyodbc-1.3.3-py3.5.egg\pypyodbc.py", line 1275, in _BindParams
if param_types[col_num][0] == 'u':
TypeError: 'type' object is not subscriptable
新代码(编辑):
import pypyodbc
connection = pypyodbc.connect('Driver={SQL Server};'
'Server=x;'
'Database=y;'
'uid=x;pwd=y')
cursor = connection.cursor()
NbFiche=0
L=[[4702, 3095, 3543], [2040, 2030, 2020]]
for log in L:
log=tuple(log) # I also tried with a list
SQLCommand = ("select count(*) from PRODUCTION where ID_TV IN (?) ")
cursor.execute(SQLCommand,(log,))
results = cursor.fetchone()
NbFiche += results[0]
编辑:
import pypyodbc
connection = pypyodbc.connect('Driver={SQL Server};'
'Server=x;'
'Database=y;'
'uid=x;pwd=y')
cursor = connection.cursor()
NbFiche=0
L=[[4702, 3095], [2040, 2030, 2020]]
for log in L:
SQLCommand = ("select count(*) from PRODUCTION where ID_TV IN (?)")
params = ','.join(map(str,log))
cursor.execute(SQLCommand,params)
results = cursor.fetchone()
NbFiche += results[0]
结果如下:
Traceback (most recent call last):
File "//Srvaktct-bur02/telecontact/TCT TRAVAIL/Pôle Fichier/AMIRA/STATISTIQUES/nimp.py", line 13, in <module>
cursor.execute(SQLCommand,params)
File "C:\Users\admin_fichier\AppData\Local\Programs\Python\Python35\lib\site-packages\pypyodbc-1.3.3-py3.5.egg\pypyodbc.py", line 1454, in execute
raise TypeError("Params must be in a list, tuple, or Row")
TypeError: Params must be in a list, tuple, or Row
答案 0 :(得分:0)
我认为因为你有一个空列表:
L=[[4702, 3095, 3543], [2040, 2030, 2020], []]
^^
使用if
进行测试时,即使列表为空,也会通过测试,类似于以下示例:
>>> l = []
>>> if l is not None:
print('l is not empty')
l is not empty
事实上哪个是错的,所以,要解决这个问题,请执行以下操作:
>>> if l:
print('l is not empty')
else:
print('l is Empty')
l is Empty
因此,将测试表达式更改为:
if log:
if len(log)==3:
#...
编辑:
如果log
的长度是可变长度的,那么您可能必须首先构建字符串参数,然后将其传递给cursor.execute
方法,这样:
SQLCommand = "select count(*) from PRODUCTION where ID_TV IN ({}) "
params = ','.join(map(str,log))
cursor.execute(SQLCommand.format(params))
EDIT2:
如果params是用户输入数据,则先前提出的解决方案会遇到SQL_injections漏洞。因此,更好的方法是将它们作为参数传递给cursor.execute
方法:
L=[[4702, 3095, 3543], [2040, 2030, 2020]]
for log in L:
if log:
SQLCommand = "select count(*) from PRODUCTION where ID_TV IN ?"
cursor.execute(SQLCommand, tuple(log))
如果您有多个参数:
SQLCommand = "select ?, ? from PRODUCTION where ID_TV IN ?"
cursor.execute(SQLCommand, (p1, p2, tuple(log)))