说我有一个'宽'的密封类层次结构:
sealed trait Alphabet
case class A(word: String) extends Alphabet
...
case class Z(word: String) extends Alphabet
并说我为层次结构中的每个子类定义了一个类型类实例:
trait SwearWordFinder[T <: Alphabet] {
def isSwearWord(x: T): Boolean
}
val swearWordFinderA = new SwearWordFinder[A] { ... }
...
val swearWordFinderZ = new SwearWordFinder[Z] { ... }
有没有办法可以为Alphabet
trait本身定义一个类型类实例,而不必通过模式匹配来实现它(如下所示)?
def isSwearWord(x: Alphabet): Boolean = x match {
case a: A => swearWordFinderA.isSwearWord(a)
...
case z: Z => swearWordFinderZ.isSwearWord(z)
}
答案 0 :(得分:4)
您可以将Alphabet
表示为Coproduct
的无形A :+: B :+: ... :+: Z :+: CNil
,如果SwearWordFinder
A
,B
, ..并定义CNil
和:+:
的实例,您可以使用其通用表示形式获得SwearWordFinder[Alphabet]
。
import shapeless._
trait SwearWordFinder[T] {
def isSwearWord(x: T): Boolean
}
object SwearWordFinder extends SwearWordFinder0 {
implicit def apply[T](implicit swf: SwearWordFinder[T]): SwearWordFinder[T] = swf
implicit val cnilSwearWordFinder: SwearWordFinder[CNil] =
new SwearWordFinder[CNil] {
def isSwearWord(t: CNil): Boolean = false
}
implicit def coproductConsSwearWordFinder[L, R <: Coproduct](implicit
lSwf: SwearWordFinder[L],
rSwf: SwearWordFinder[R]
): SwearWordFinder[L :+: R] =
new SwearWordFinder[L :+: R] {
def isSwearWord(t: L :+: R): Boolean =
t.eliminate(lSwf.isSwearWord, rSwf.isSwearWord)
}
}
trait SwearWordFinder0 {
implicit def genericSwearWordFinder[T, G](implicit
gen: Generic.Aux[T, G],
swf: Lazy[SwearWordFinder[G]]
): SwearWordFinder[T] =
new SwearWordFinder[T] {
def isSwearWord(t: T): Boolean = swf.value.isSwearWord(gen.to(t))
}
}
现在我们的信件的一些例子:
sealed trait Alphabet extends Product with Serializable
object Alphabet {
final case class A(word: String) extends Alphabet
final case class Z(word: String) extends Alphabet
}
implicit val swfA = new SwearWordFinder[Alphabet.A] {
def isSwearWord(a: Alphabet.A) = a.word == "apple"
}
implicit val swfZ = new SwearWordFinder[Alphabet.Z] {
def isSwearWord(z: Alphabet.Z) = z.word == "zebra"
}
现在我们可以获得SwearWordFinder[Alphabet]
:
def isBadWord[T](t: T)(implicit swfT: SwearWordFinder[T]): Boolean =
swfT.isSwearWord(t)
val a1: Alphabet = Alphabet.A("apple")
val z2: Alphabet = Alphabet.Z("zorro")
val z3: Alphabet = Alphabet.Z("zebra")
isBadWord(a1) // true
isBadWord(z2) // false
isBadWord(z3) // true
就像我在评论中提到的那样:谨防SI-7046。您的Alphabet
AST需要位于具有SwearWordFinder
的项目所依赖的项目中,或者包含在将在具有Alphabet
类型类派生的包之前编译的包中。