从年和朱利安日在熊猫中创建日期时间

Question

                  ad_name    adl_name  year  JD 
0  united_states_of_america  colorado  2000   1 
1  united_states_of_america  colorado  2000   2 
2  united_states_of_america  colorado  2000   3 
3  united_states_of_america  colorado  2000   4 
4  united_states_of_america  colorado  2000   5 

如何使用year和JD（朱利安日）列添加日期时间列？我试图使用：

pd.to_datetime(df, format='%Y_%d')，但这不起作用

Answer 1

您需要添加year列JD已转换Ansible Documentation：

df['date'] = pd.to_datetime(df.year, format='%Y') + pd.to_timedelta(df.JD - 1, unit='d')
print (df)
                    ad_name  adl_name  year  JD       date
0  united_states_of_america  colorado  2000   1 2000-01-01
1  united_states_of_america  colorado  2000   2 2000-01-02
2  united_states_of_america  colorado  2000   3 2000-01-03
3  united_states_of_america  colorado  2000   4 2000-01-04
4  united_states_of_america  colorado  2000   5 2000-01-05

JD=32和JD=366的示例：

print (df)
                    ad_name  adl_name  year   JD
0  united_states_of_america  colorado  2000   32
1  united_states_of_america  colorado  2000  366

df['date'] = pd.to_datetime(df.year, format='%Y') + pd.to_timedelta(df.JD - 1, unit='d')
print (df)
                    ad_name  adl_name  year   JD       date
0  united_states_of_america  colorado  2000   32 2000-02-01
1  united_states_of_america  colorado  2000  366 2000-12-31