Question

<?php

error_reporting(1);

$con=mysql_connect("localhost","root","");

mysql_select_db("demo",$con);

extract($_POST);

$target_dir = "test_upload/";

$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);

if($upd)
{
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);

if($imageFileType != "mp4" && $imageFileType != "avi" && $imageFileType != "mov" && $imageFileType != "3gp" && $imageFileType != "mpeg")
{
    echo "File Format Not Suppoted";
} 

else
{

$video_path=$_FILES['fileToUpload']['name'];

mysql_query("insert into video(video_name) values('$video_path')");

move_uploaded_file($_FILES["fileToUpload"]["tmp_name"],$target_file);

echo "uploaded ";

}

}

//display all uploaded video

if($disp)

{

$query=mysql_query("select * from video");

    while($all_video=mysql_fetch_array($query))

    {
?>

     <video width="300" height="200" controls>
    <source src="test_upload/<?php echo $all_video['video_name']; ?>" type="video/mp4">
    </video> 

    <?php } } ?>


<form method="post" enctype="multipart/form-data">

<table border="1">

<tr>

<Td>Upload  Video</td></tr>

<Tr><td><input type="file" name="fileToUpload"/></td></tr>

<tr><td>

<input type="submit" value="Uplaod Video" name="upd"/>

<input type="submit" value="Display Video" name="disp"/>

</td></tr>

</table>

</form>

使用此代码我尝试上传视频。 视频名称已正确保存在数据库中，但问题是特定文件夹中的视频无法移动。因此，当我编写选择查询时，该时间视频不会显示。

任何人，请帮我解释一下。

我是编程语言的新手

Answer 1

首先移动到文件夹，如果移动，则插入数据库。然后，检查服务器的最大上传大小。

   if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        mysql_query("insert into video(video_name) values('$video_path')");
        echo "Uploaded successfully";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }

更改您的php.ini文件upload_max_filesize和post_max_size，无论您想要的大小。示例i给出100M - 100MB

; Maximum allowed size for uploaded files.
upload_max_filesize = 100M 

; Must be greater than or equal to upload_max_filesize
post_max_size = 100M

使用MySQL和PHP上传视频

1 个答案: