Question

我在youtube视频后学习改造但是现在我被卡住了。它向我显示了一个错误＆＃34;改进了预期的begin_array，但是在第1行第2列路径上的begin_object $＆＃34; 我试图从这个网站获取json数据。 http://servicio-monkydevs.rhcloud.com/clientes/

这是我的代码

MainActivity.java

resultadoTextView = (TextView) findViewById(R.id.Resultado);
    Retrofit restAdapter = new Retrofit.Builder()
            .baseUrl("http://servicio-monkydevs.rhcloud.com")
            .addConverterFactory(GsonConverterFactory.create())
            .build();

    ClienteService service = restAdapter.create(ClienteService.class);
    Call<Cliente> call = service.getCliente();
    call.enqueue(new Callback<Cliente>() {
        @Override
        public void onResponse(Call<Cliente> call, Response<Cliente> response) {
            if(response.isSuccessful()) {
                resultadoTextView.setText(call.toString());
            }else{
                resultadoTextView.setText("algo paso");
            }
        }

        @Override
        public void onFailure(Call<Cliente> call, Throwable t) {
            resultadoTextView.setText(t.getMessage());
        }
    });

ClientService.java

public interface ClienteService {
  @GET("/clientes")
  Call<Cliente> getCliente();
}

Client.java

public class Cliente {
private int id;
private String name;
private String username;
private String email;
private String phone;
private String website;
private String photo;

public int getId() {
    return id;
}

public void setId(int id) {
    this.id = id;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public String getUsername() {
    return username;
}

public void setUsername(String username) {
    this.username = username;
}

public String getEmail() {
    return email;
}

public void setEmail(String email) {
    this.email = email;
}

public String getPhone() {
    return phone;
}

public void setPhone(String phone) {
    this.phone = phone;
}

public String getWebsite() {
    return website;
}

public void setWebsite(String website) {
    this.website = website;
}

public String getPhoto() {
    return photo;
}

public void setPhoto(String photo) {
    this.photo = photo;
}

@Override
public String toString() {
    return "Cliente{" +
            "id=" + id +
            ", name='" + name + '\'' +
            ", username='" + username + '\'' +
            ", email='" + email + '\'' +
            ", phone='" + phone + '\'' +
            ", website='" + website + '\'' +
            ", photo='" + photo + '\'' +
            '}';
}}

我做错了什么？

更新

我做了这些修改

public class Cliente {
@SerializedName("id")
private int id;
@SerializedName("name")
private String name;
@SerializedName("username")
private String username;
@SerializedName("email")
private String email;
@SerializedName("phone")
private String phone;
@SerializedName("website")
private String website;
@SerializedName("photo")
private String photo;
...

这在界面中

public interface ClienteService {
  @GET("/clientes")
  Call<List<Cliente>> getCliente();
}

这就像你说的那样在MainActivity中

 Call<List<Cliente>> call = service.getCliente();
    call.enqueue(new Callback<List<Cliente>>() {
        @Override
        public void onResponse(Call<List<Cliente>> call, Response<List<Cliente>> response) {
            if(response.isSuccessful()) {
                resultadoTextView.setText(call.toString());
            }else{
                resultadoTextView.setText("algo paso");
            }
        }

        @Override
        public void onFailure(Call<List<Cliente>> call, Throwable t) {
            resultadoTextView.setText(t.getMessage());
        }
    });

但现在它向我显示了这个错误：的＆＃34; retrofit2.executorCallAdapterFactory$ExecutorCallbackCall@6a3dd44"

它在这一行显示了我

...
if(response.isSuccessful()) {
            resultadoTextView.setText(call.toString());  <-- HERE
        }else{
...

Answer 1

正如您所看到的给定REST API url返回一个Object数组，即ArrayList，但在您的改装api服务中，返回类型为Only Cliente。因此，将ClientService.java更改为以下

public interface ClienteService {
 @GET("/clientes")
 Call<List<Cliente>> getCliente();
}

将Call.enque（）方法更改为此

Call<List<Cliente>> call = service.getCliente();
    call.enqueue(new Callback<List<Cliente>>() {
        @Override
        public void onResponse(Call<List<Cliente>> call, Response<List<Cliente>>  response) {
            if(response.isSuccessful()) {
               // your code to get data from the list
            }else{

            }
        }

        @Override
        public void onFailure(Call<List<Cliente>> call, Throwable t) {
            resultadoTextView.setText(t.getMessage());
        }
    });

Answer 2

首先，您需要将Call<Client>更改为Call<List<Client>>，因为响应返回列表对象客户端。
其次准备Class Client 实施 Serializable以支持解析

我认为已经完成了

改造预期begin_array但是在第1行第2列路径$的begin_object

2 个答案: