Question

如何改进这个mysql视图？

我认为没有必要执行两个子查询，这两个子查询同时访问具有相同jc_donation_method = WHERE CLAUSE但不同d.donation_method = m.donation_method的同一个表SELECT CLAUSEL。但我不知道要避免这种情况。

donation_id是jc_donation中的主键和jc_donation_method中的外键。

CREATE
  OR REPLACE
  ALGORITHM = MERGE
  VIEW jc_donation_total AS
SELECT
  d.donation_method,
  (SELECT
      m.method_name
   FROM
      `jc_donation_method` m
   WHERE
      d.donation_method = m.donation_method
  LIMIT 1) method_name,
  CAST(SUM(d.donation_amount-
    (SELECT
        m.method_fee_nonrecurring
     FROM
        `jc_donation_method` m
     WHERE
        d.donation_method = m.donation_method
     LIMIT 1)
  - d.donation_amount*(
  (SELECT
      m.method_fee_percent
   FROM
      `jc_donation_method` m
   WHERE
      d.donation_method = m.donation_method
   LIMIT 1))
  ) as decimal(12,4)) donation_total
FROM
  `jc_donation` d
LEFT JOIN
  `jc_user` u
ON
  d.user_id = u.user_id
GROUP BY
  d.donation_method
HAVING
  COUNT(u.user_id) > 0

基本上我想知道活动用户每次捐赠所做的所有捐赠方式：金额 - 非经常性费用 - 百分比费用％（每次捐赠）。

先决条件：

CREATE TABLE `jc_user` (
  `user_id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT,
  PRIMARY KEY (`user_id`) USING BTREE
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='User credentials';

CREATE TABLE `jc_donation_method` (
  `donation_method` int(10) UNSIGNED NOT NULL AUTO_INCREMENT,
  `method_name` varchar(32) NOT NULL,
  `method_fee_percent` decimal(6,4) NOT NULL DEFAULT 0.00,
  `method_fee_nonrecurring` decimal(5,2) NOT NULL DEFAULT 0.00,
  PRIMARY KEY (`donation_method`) USING BTREE,
  UNIQUE KEY `method_name` (`method_name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='Donation methods and fees';

INSERT INTO
  `jc_donation_method` (`donation_method`, `method_name`,
  `method_fee_percent`, `method_fee_nonrecurring`)
VALUES
  (NULL, 'Transfer',0.000,0.00),
  (NULL, 'PayPal',0.0190,0.35);

CREATE TABLE `jc_donation` (
  `donation_id` int(10) NOT NULL AUTO_INCREMENT,
  `user_id` int(10) UNSIGNED NOT NULL,
  `donation_method` int(10) UNSIGNED NOT NULL DEFAULT '1',
  `donation_amount` decimal(12,4) NOT NULL,
  PRIMARY KEY (`donation_id`) USING BTREE,
  FOREIGN KEY (user_id) REFERENCES jc_user(user_id),
  FOREIGN KEY (donation_method) REFERENCES jc_donation_method(donation_method)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='Donations';

Answer 1

正如我在最初的评论中所说，我不确定为什么用户是相关的，但这应该是最简单的查询来获得你想要的东西：

SELECT m.donation_method, m.method_name
  , CAST(
      d.donation_amount 
      - m.method_fee_nonrecurring 
      - (d.donation_amount * m.method_fee_percent)
    AS DECIMAL(12, 4)) donation_total
FROM jc_donation_method AS m
INNER JOIN jc_donation AS d
ON m.donation_method = d.donation_method
GROUP BY m.donation_method
;

以下版本应该像原作一样考虑用户。

SELECT m.donation_method, m.method_name
  , CAST(
      d.donation_amount 
      - m.method_fee_nonrecurring 
      - (d.donation_amount * m.method_fee_percent)
    AS DECIMAL(12, 4)) donation_total
FROM jc_donation_method AS m
INNER JOIN jc_donation AS d
INNER JOIN jc_user AS u ON d.user_id = u.user_id
ON m.donation_method = d.donation_method
GROUP BY m.donation_method
;

是否有可能避免访问同一个表的两个子查询？

1 个答案: