在我收到几乎相同的错误信息之前,我遇到了类似的问题,即
C:\Users\David J\optilab\optilab_project>python functional_tests.py
Traceback (most recent call last):
File "functional_tests.py", line 4, in <module>
from optilab.models import Design
File "C:\Users\David J\optilab\optilab_project\optilab\models.py", line 10, in <module>
class Design(models.Model):
File "C:\Users\David J\optilab\optilab_project\optilab\models.py", line 11, in Design
name = models.CharField(max_length=30)
File "C:\Python27\lib\site-packages\django\db\models\fields\__init__.py", line 1072, in __init__
super(CharField, self).__init__(*args, **kwargs)
File "C:\Python27\lib\site-packages\django\db\models\fields\__init__.py", line 166, in __init__
self.db_tablespace = db_tablespace or settings.DEFAULT_INDEX_TABLESPACE
File "C:\Python27\lib\site-packages\django\conf\__init__.py", line 55, in __getattr__
self._setup(name)
File "C:\Python27\lib\site-packages\django\conf\__init__.py", line 41, in _setup
% (desc, ENVIRONMENT_VARIABLE))
django.core.exceptions.ImproperlyConfigured: Requested setting DEFAULT_INDEX_TABLESPACE, but settings are not configured. You must either define the environment variable DJANGO_SETTINGS_MODULE or call settings.configure() before accessing settings.
但它正在制作,因为我从shell中错误地调用了我的测试。现在我正在尝试运行一个功能测试,在成功使用该命令之前,我已经做了好几次
"python functional_tests.py"
在我的项目文件夹中 - 但它产生上述错误消息。任何人都可以告诉我我做错了什么,或者为什么这可能以前有效但现在不行?感谢。
编辑: 这是functional_tests.py:
from selenium import webdriver
import unittest
from selenium.webdriver.common.keys import Keys
from optilab.models import Design
from automa.api import *
class HomeTest(unittest.TestCase):
def setUp(self):
self.browser = webdriver.Firefox()
self.browser.get('http://localhost:8000/lab')
self.new_design = self.browser.find_element_by_id("new_design")
self.load_design = self.browser.find_element_by_id("load_test")
self.design_name = self.browser.find_element_by_id("design_name")
self.browser.implicitly_wait(3)
def test_latest_designs_displayed_in_table(self):
#
self.browser.implicitly_wait(3)
self.design_table = self.browser.find_element_by_id("design_table")
self.rows = self.browser.find_elements_by_tag_name('tr')
self.assertTrue(
any(row.text == 'My First Design' for row in rows),
"New design did not appear in test table."
)
def test_entering_text_activates_new(self):
# user enters name of design. new becomes clickable.
self.browser.implicitly_wait(3)
self.design_name.send_keys("sample_design")
def test_new_test_can_be_saved_and_retrieved(self):
name = "sample design"
self.design_name.send_keys(name)
self.new_design.click()
self.browser.implicitly_wait(3)
self.saved_design = Design.objects.get(name=design_name)
def test_entering_name_of_previously_saved_test_activates_load(self):
# user enters the name of a previously saved test. load button becomes clickable.
design = Design(name="sample_design")
saved_design = Design.objects.get(id=1).name
self.browser.implicitly_wait(3)
self.design_name.send_keys(saved_design)
self.load_design.click()
def test_entering_name_of_previously_saved_test_but_clicking_new_prompts_overwrite(self):
# user entes name of saved test but clicks new. dialogue box asks if test should be overwritten.
previously_saved_design = Design.objects.get(id=1).name
self.design_name.send_keys(previously_saved_design)
def test_clicking_save_redirects_to_model(self):
pass
def tearDown(self):
self.browser.quit()
if __name__ == '__main__':
unittest.main()
答案 0 :(得分:1)
脚本的开头看起来应该是这样的
import os, sys
sys.path.append(os.getcwd())
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "optilab.settings") # or whatever
import django
django.setup()
from selenium import webdriver
import unittest
from selenium.webdriver.common.keys import Keys
from optilab.models import Design
from automa.api import * # try not to do this
答案 1 :(得分:0)
这是因为在尝试调用设置之前没有正确设置Django,如果没有django.setup()
变量,则无法知道应该使用哪些项目设置,manage.py test
调用对于导入是必不可少的模型和访问数据库。 (有关该方法,请参阅e4c5's answer)
但是,这不是推荐的方法或最简单的方法。您可以像manage.py test
中的单元测试一样调用功能测试,Django将为您自动设置所有内容,它甚至可以使用tempdb进行功能测试。如果你的功能测试包括功能测试中的插入和更新(你应该),tempdb会派上用场。
要使用此功能,您必须更改代码中的一些内容。
首先是文件名的问题,-p
(doc)的默认模式是&#34; test * .py&#34;,您可以使用{{1}更改此内容}或--pattern
但通常的解决方案是将functional_tests.py重命名为tests.py并将其放在functional_tests文件夹中。这样,您可以通过调用manage.py test functional_tests
来调用功能测试。
此外,您应该考虑使用TestCase
或django.test
(doc)中的LiveServerTestCase
(doc)而不是从unittest导入TestCase省去了自己运行manage.py runserver
的麻烦。