Question

我正在尝试将混合类型的元组拼成一个列表。以下函数不会产生所需的输出：

a = (1, 2, 3, ['first', 'second'])
def flatten(l): 
return flatten(l[0]) + (flatten(l[1:]) if len(l) > 1 else []) if type(l) is list else [l]

>>> flatten(a)
[(1, 2, 3, ['first', 'second'])]
>>> flatten(flatten(a))
[(1, 2, 3, ['first', 'second'])]
>>> [flatten(item) for item in a]
[[1], [2], [3], ['first', 'second']]

输出应为：

>>> [1, 2, 3, 'first', 'second']

Answer 1

def flatten(l):
    if isinstance(l, (list,tuple)):
        if len(l) > 1:
            return [l[0]] + flatten(l[1:])
        else:
            return l[0]
    else:
        return [l]

a = (1, 2, 3, ['first', 'second'])

print(flatten(a))

[1,2,3，＆＃39; first＆＃39;，＆＃39; second＆＃39;]

如何取消混合类型的元组？

1 个答案: