Question

我有一个名为player的嵌套列表，如下所示：

players = [["PlayerA", "10", "20"], ["PlayerB", "15", "30"], ["PlayerC", "15", "30"] ]

我希望能够使用输入语句按播放器名称（PlayerA，PlayerB等）进行搜索，如果搜索与项目匹配，则打印出整个项目。我将如何做到这一点，我正在尝试学习不同的方法。

search = input("Please enter the players name")
for item in players:
  if item == search:
     print(item)
  else:
     print("item not found")

当我执行上述操作时，它会继续打印未找到的项目。

非常感谢提前。

Answer 1

if item == search:

此条件不会成功，因为item为["PlayerA", "10", "20"]，search为"PlayerA"。列表永远不会与字符串相等。

尝试将search与item的第一个元素进行比较。

if item[0] == search:

Answer 2

它未打印＆＃34;项目的原因＆＃34;是因为您要将子列表与要查找的字符串进行比较，例如

["PlayerA", "10", "20"] == "PlayerA"

当然是假的。您需要从每个子列表中提取名称。

您可以这样做的一种方法是使用filter，如下所示：

filter(lambda record: record[0] == "PlayerA", players)

这将返回一个记录列表，其中第0个元素匹配＆＃34; PlayerA＆＃34;。

Answer 3

您需要访问第一个元素或嵌套列表。像这样：

for player in players:
    if player[0] == input:
        return player

Answer 4

是的，只是让你像这样编码：

players = [["PlayerA", "10", "20"], ["PlayerB", "15", "30"], ["PlayerC", "15", "30"] ]
search = input("Please enter the players name: ")

result = [player for player in players if player[0] == search]

if result == []:
    print("item not found")
else:
    print(result)

Python搜索嵌套列表

4 个答案: