正则表达式替换以删除字符串前缀中的数字

Question

如何删除字符串＆＃39; Tech search＆＃39;？

之前的数字

'502402849 - Tech search;502489756 - world wide;123698745 - Tech search to'

注意： - 仅限＆＃39;技术搜索＆＃39;不是之前＆＃39;技术搜索到＆＃39;

Answer 1

可用于匹配您要替换的数字的一个正则表达式是：

\d+\s-\sTech search;

SELECT REGEXP_REPLACE (col, '\d+\s-\sTech search(;|$)', '')

在这里测试正则表达式：

Answer 2

查询1 ：

WITH data ( value ) AS (
  SELECT '502402849 - Tech search;502489756 - world wide;123698745 - Tech search to'
  FROM   DUAL
)
SELECT REGEXP_REPLACE( value, '^\d+' ) AS out
FROM   data;

<强>输出：

OUTPUT                                                         
----------------------------------------------------------------
 - Tech search;502489756 - world wide;123698745 - Tech search to 

查询2 ：

WITH data ( value ) AS (
  SELECT '502402849 - Tech search;502489756 - world wide;123698745 - Tech search to'
  FROM   DUAL
)
SELECT REGEXP_REPLACE( value, '\d+\s*-\s*(Tech search(;|$))', '\1' ) AS output
FROM   data;

<强>输出：

OUTPUT                                                      
-------------------------------------------------------------
Tech search;502489756 - world wide;123698745 - Tech search to 

查询3 ：

WITH data ( value ) AS (
  SELECT '502402849 - Tech search;502489756 - world wide;123698745 - Tech search to'
  FROM   DUAL
)
SELECT REGEXP_REPLACE( value, '\d+\s*-\s*(Tech search(;|$))' ) AS output
FROM   data;

<强>输出：

OUTPUT                                                      
-------------------------------------------------
502489756 - world wide;123698745 - Tech search to 

Answer 3

regexp_replace（＆＃39; 502402849 - 技术搜索; 502489756 - 全球范围; 123698745 - 技术搜索到＆＃39;，＆＃39; \ d +（？= - 技术搜索;）＆＃39;，＆＃39 ;＆＃39）;