我有基于树的数据模型。我需要在树查看器上显示树,并在元素查看器上显示元素树之一,如此方案:
tree viewer | element viewer:
Element A | There should be content from selected element (Element C).
-Element B |
-Element C |
(Selected)|
树查看器和元素查看器都可以对模型进行更改。
现在我有以下代码:
public class TreeNode{...};
public class AClass extends TreeNode{...};
public class BClass extends TreeNode{...};
public class CClass extends TreeNode{...};
public class Viewer{
...
//Specifies how to display data from a treeNode
public abstract void showModel();
...
};
public class AViewer extends Viewer{...};
public class BViewer extends Viewer{...};
public class CViewer extends Viewer{...};
public class Controller{
...
public void chooseViewer(TreeNode treeNode ){
if (treeNode instanceof AClass) elementViewer = new AViewer(treeNode);
else if (treeNode instanceof BClass) elementViewer = new BViewer(treeNode);
else if (treeNode instanceof CClass) elementViewer = new CViewer(treeNode);
}
}
从OOP和MVC设计模式的角度来看,如何正确解决这个问题呢?
答案 0 :(得分:1)
MVC和OOP有时会发生冲突。话虽如此,似乎解决方案似乎只是将查看器选择移动到树节点:
public class TreeNode {
Viewer getViewer();
}