Question

这里我有两个表pro_zone_m和temp_const，我将值插入第三个表pro_m，我将从temp_const插入区域，我需要从pro_zone_m获取相应区域的zone_id的值。我尝试但无法想出解决方案。

$uisq = "SELECT * FROM pro_zone_m";
$ytu = mysql_query($uisq);
$mnm = mysql_fetch_array($ytu);
extract($mnm);


$wqr = "SELECT * FROM temp_const";
$wqe = mysql_query($wqr);
while($wqe1 = mysql_fetch_array($wqe))
{
extract($wqe1);


$zxc = "INSERT INTO pro_m set custid='$custid', firstname='$firstname',     lastname='$lastname', country='$country', 
city='$city', state='$state', zone='$zone', adresstype='$address_type',     address1='$address1', address2='$address2',category='$category', 
focus='$focus', assignto='$assign_to', division='$division',     product='$product', grade='$grade', potential='$potential',     designtn='$designation',
mobile='$mobile', primphone='$primary_phone', primemail='$primary_email',
exhibition = '$exhibition',  zonea_id = '$zoneid' WHERE zone = '$code' ";

$zxc1 = mysql_query($zxc);

Answer 1

更新您的插入查询，如下所示:(假设zonea_id将存储temp_const表中的zone_id。

$ zxc =＆＃34; INSERT INTO pro_m set custid =＆＃39; $ custid＆＃39;，firstname =＆＃39; $ firstname＆＃39;，lastname =＆＃39; $ lastname＆＃39;，国家=＆＃39; $国家＆＃39 ;, city =＆＃39; $ city＆＃39;，state =＆＃39; $ state＆＃39;，zone =＆＃39; $ zone＆＃39;，adresstype =＆＃39; $ address_type＆＃39;，address1 = ＆＃39; $ address1＆＃39;，address2 =＆＃39; $ address2＆＃39;，category =＆＃39; $ category＆＃39;，焦点=＆＃39; $ focus＆＃39;，assignto =＆＃39; $ assign_to＆＃39;，division =＆＃39; $ division＆＃39;，product =＆＃39; $ product＆＃39;，grade = ＆＃39; $ grade＆＃39;，potential =＆＃39; $ potential＆＃39;，designtn =＆＃39; $ designation＆＃39;， mobile =＆＃39; $ mobile＆＃39;，primphone =＆＃39; $ primary_phone＆＃39;，primemail =＆＃39; $ primary_email＆＃39;， exhibition =＆＃39; $ exhibition＆＃39;， zonea_id =（SELECT zone_id FROM temp_const where zone =＆＃39; $ code＆＃39;）＆＃34;;

如何在两个表中插入值在一个表中的值等于另一个表中的值？

1 个答案: