Question

to argument is list right，所以这里有什么不对我正在尝试发送到to_email

中的多个地址

from django.core.mail import send_mail
from django.conf import settings


subject = 'Where is the fault'
from_email = settings.EMAIL_HOST_USER
to_email = [from_email , 'otheremail@email.com']
contact_message = "%s: %s via %s" % (
    form_full_name , 
    form_message , 
    form_email)

send_mail(
    'subject',
    'contact_message.',
    'from_email',
    'to_email',
    fail_silently=False,
)

这意味着什么。我已经在settings.py文件中完成了设置，看起来像这样。

EMAIL_USE_TLS = True
EMAIL_HOST = 'smtp.gmail.com'
EMAIL_HOST_USER = 'anything@gmail.com'
EMAIL_HOST_PASSWORD = 'password'
EMAIL_PORT = 587

Answer 1

在send_mail部分中，您需要参考列表，而不是引用未定义的字符串...

将其更改为此应该有效：

from django.core.mail import send_mail
from django.conf import settings


subject = 'Where is the fault'
from_email = settings.EMAIL_HOST_USER
to_email = [from_email , 'otheremail@email.com']
contact_message = "%s: %s via %s" % (
    form_full_name , 
    form_message , 
    form_email)

send_mail(
    subject,
    contact_message.,
    from_email,
    to_email,
    fail_silently=False,
)

＆＃34;至＆＃34;在配置send_mail时，参数必须是列表或元组

1 个答案: