Question

我是第一次使用Web scraper，我使用Beautiful Soup来解析JSON文件并返回我发送给CSV的几个属性。

JSON数组中的status变量是二进制值（0/1）。我只想返回状态为0的数组。这样做是否可行？

"""soup = BeautifulSoup(html)
table = soup.find()
print soup.prettify()"""
js_data = json.loads(html)
Attraction = []
event = []
status = []
for doc in js_data["response"]["docs"]:
    Attraction.append(doc["Attraction"])
    event.append(doc["PostProcessedData"]["Onsales"]["event"]["date"])
    status.append(doc["PostProcessedData"]["Onsales"]["status"])
with open("out.csv","w") as f:
    datas = zip(Attraction,event,status)
    keys = ["Attraction","event","status"]
    f.write(";".join(keys))
    for data in datas:
        f.write(",".join([str(k).replace(",",";").replace("<br>"," ") for k in data]))
        f.write("\n")

Answer 1

我可能会遗漏一些东西，但也许这会有所帮助：

for doc in js_data["response"]["docs"]:
    if doc["PostProcessedData"]["Onsales"]["status"] == "0":
        Attraction.append(doc["Attraction"])
        event.append(doc["PostProcessedData"]["Onsales"]["event"]["date"])
        status.append(doc["PostProcessedData"]["Onsales"]["status"])

BeautifulSoup可以找到具有匹配值的元素吗？

1 个答案: