Question

这是我的第一篇文章。我总是来这个论坛寻找代码的答案。

我一直在努力理解Python中的正则表达式，但它有点难。

我的文字看起来像这样：

Name:   Clash1
Distance:   -1.341m
Image Location: Test 1_navis_files\cd000001.jpg
HardStatus: New
Clash Point:    3.884m, -2.474m, 2.659m
Date Created:   2016/6/2422:45:09

Item 1
GUID:   6efaec51-b699-4d5a-b947-505a69c31d52
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Pipes (1) ->Pipe Types (1) ->Default (1) ->Pipe Types [2463] ->Shell
Item Name:  Pipe Types [2463]
Item Type:  Shell

Item 2
GUID:   6efaec51-b699-4d5a-b947-505a69c31dea
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Walls (4) ->Basic Wall (4) ->Wall 1 (4) ->Basic Wall [2343] ->Shell
Item Name:  Basic Wall [2343]
Item Type:  Shell

------------------


Name:   Clash2
Distance:   -1.341m
Image Location: Test 1_navis_files\cd000002.jpg
HardStatus: New
Clash Point:    3.884m, 3.533m, 2.659m
Date Created:   2016/6/2422:45:09

Item 1
GUID:   6efaec51-b699-4d5a-b947-505a69c31d52
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Pipes (1) ->Pipe Types (1) ->Default (1) ->Pipe Types [2463] ->Shell
Item Name:  Pipe Types [2463]
Item Type:  Shell

Item 2
GUID:   6efaec51-b699-4d5a-b947-505a69c31de8
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Walls (4) ->Basic Wall (4) ->Wall 1 (4) ->Basic Wall [2341] ->Shell
Item Name:  Basic Wall [2341]
Item Type:  Shell

------------------

我需要做的是创建一个列表，为每个文本块（由-------------------------------分隔）提取以下内容作为字符串：冲突名称和冲突点。

例如：Clash 1 3.884, 3.533, 2.659

我对Python很陌生，对正则表达式真的不太了解。

有人能给我一些关于使用正则表达式从文本中提取这些值的线索吗？

我做了类似的事情：

exp = r'(?<=Clash Point\s)(?<=Point\s)([0-9]*)'
match = re.findall(exp, html)

if match:
    OUT.append(match)
else:
    OUT = 'fail'

但我知道我远离我的目标。

Answer 1

如果您正在寻找正则表达式解决方案，您可以提出：

^Name:\s*         # look for Name:, followed by whitespaces
                  # at the beginning of a line
(?P<name>.+)      # capture the rest of the line
                  # in a group called "name"
[\s\S]+?          # anything afterwards lazily
^Clash\ Point:\s* # same construct as above
(?P<point>.+)     # same as the other group

请参阅a demo on regex101.com

<小时/> 转换为Python代码，这将是：

import re
rx = re.compile(r"""
                ^Name:\s*
                (?P<name>.+)
                [\s\S]+?
                ^Clash\ Point:\s*
                (?P<point>.+)""", re.VERBOSE|re.MULTILINE)

for match in rx.finditer(your_string_here):
    print match.group('name')
    print match.group('point')

这将输出：

Clash1
3.884m, -2.474m, 2.659m
Clash2
3.884m, 3.533m, 2.659m

请参阅a working demo on ideone.com。

Answer 2

import re


lines = s.split('\n')

names = []
points = []

for line in lines:    
    result = re.search('^Name:\s*(\w+)', line)
    if result:
        names.append(result.group(1))

    result = re.search('^Clash Point:\s*([-0-9m., ]+)',line)
    if result:
        points.append(result.group(1))

print(names)
print(points)

# if you need more nice output, you can use zip() function
for name, point in zip(names, points):
    print(name, point)

您可以在regexr.com上找到有关正则表达式的有用信息。另外，我用它来快速测试和参考。

特定的正则表达式搜索python

2 个答案: