' sliderChanged:无法识别的选择器发送到实例'

时间:2016-06-26 16:22:08

标签: ios swift uitableview uislider

我创建了一个滑块和一个文本标签来显示滑块的值。两者都以编程方式完成:

np.logical_xor

在我的tableview中我调用函数来改变滑块的值:

class FilterCell: UITableViewCell {

override init(style: UITableViewCellStyle, reuseIdentifier: String?) {
    super.init(style: style, reuseIdentifier: reuseIdentifier)
    setupViews()
}

required init?(coder aDecoder: NSCoder) {
    fatalError("init(coder:) has not been implemented")
}

let slider : UISlider = {
    let slider = UISlider()
    slider.minimumValue = 0
    slider.maximumValue = 50
    slider.value = 50
    slider.continuous = true
    slider.userInteractionEnabled = true
    slider.translatesAutoresizingMaskIntoConstraints = false
    return slider
}()

var distanceLabel : UILabel = {
    let label = UILabel()
    label.text = "Distance: 50km"
    label.font = UIFont.systemFontOfSize(15.0)
    label.textColor = UIColor.blackColor()
    label.translatesAutoresizingMaskIntoConstraints = false
    return label
}()

func sliderChanged(sender: UISlider) {
    var sliderValue = sender.value
    distanceLabel.text = "Distance: \(sliderValue)km"
}
}

滑块和标签显示正常。当我与滑块交互以更改值时,它会崩溃并且' sliderChanged:]:无法识别的选择器发送到实例0x7fb06d0df040'。

1 个答案:

答案 0 :(得分:2)

尝试将目标添加到cell,而不是self

cell.slider.addTarget(cell, action: #selector(FilterCell.sliderChanged(_:)), forControlEvents: .ValueChanged)