Question

我有两个基于异步FileReader操作的rxjs Observable。每个订阅都单独完成，但我尝试.subscribe它们永远不会执行其let observe1 = this.Service1.parsedResponse$; let observe2 = this.Service2.parsedResponse$; observe1.subscribe((data) => { console.log('subscription 1', data); // this executes }); observe2.subscribe((data) => { console.log('subscription 2', data); // this executes }); let observeJoined = Observable.forkJoin(observe1, observe2); observeJoined.subscribe((data: Object[]) => { console.log('are we forkjoined?', data); // never happens });方法。显然我错了;继承人代码：

public interface Function<T, R> {
    /**
     * Applies this function to the given argument.
     *
     * @param t the function argument
     * @return the function result
     */
    R apply(T t);
}

public static <T, O> List<T> extract(Collection<O> collection, Function<O, T> mapper) {
    List<T> result = new ArrayList<>(collection.size());
    for (O o : collection) {
        result.add(mapper.apply(o));
    }
    return result;
}

我理想的只是两个对象（data1，data2）;它们不需要合并为一个结果。在继续之前我只需要知道我有两个。谢谢！

Answer 1

试试这个：

var source = Rx.Observable.forkJoin(
 this.Service1.parsedResponse$,
 this.Service2.parsedResponse$
);

var subscription = source.subscribe(
  function (x) {
    console.log('Next: %s', x);
  },
  function (err) {
    console.log('Error: %s', err);
  },
  function () {
    console.log('Completed');
  });

rxjs forkjoin没有exectue

1 个答案: