我是JavaScript的新手,据说我在代码中遇到了一个奇怪的错误。我的HTML中有三个图像,点击时应该以模态打开。由于某种原因,模态将卡在最后一个新图像上。例如,如果我点击第一个,然后是第三个,那么第二个,无论我点击第二个显示的是什么图像。我尝试通过将H1标签替换为图像名称进行调试,该标签抛出了另一条曲线,因为现在需要两次单击才能执行模态。我不确定我在做什么,感谢任何帮助。
JS -
<script>
function mode(param)
{
smode = param;
document.getElementById("h1thing").innerHTML = smode;
document.getElementById("myImage").src = smode;
run();
}
function run(){
// Get the modal
var modal = document.getElementById('myModal');
// Get the button that opens the modal
var btn = document.getElementById(smode);
// Get the <span> element that closes the modal
var span = document.getElementsByClassName("close")[0];
// When the user clicks the button, open the modal
btn.onclick = function() {
modal.style.display = "block";
}
// When the user clicks on <span> (x), close the modal
span.onclick = function() {
modal.style.display = "none";
smode = "";
}
// When the user clicks anywhere outside of the modal, close it
window.onclick = function(event) {
if (event.target == modal) {
modal.style.display = "none";
smode = "";
}
}
}
</script>
HTML -
<body>
<h2 id="h1thing">Modal Example</h2>
<!-- Trigger/Open The Modal -->
<center>
<div class="floated_img">
<input id="ScreenShot.png" type="image" src="ScreenShot.png" width="400" height="300" alt="ScreenShot" onclick="myFunction();mode('ScreenShot.png');">
</input>
</div>
<div class="floated_img">
<input id="ScreenShot2.png" type="image" src="ScreenShot2.png" width="400" height="300" alt="ScreenShot2" onclick="myFunction();mode('ScreenShot2.png');">
</input>
</div>
<div class="floated_img">
<input id="kimlexi.jpg" type="image" src="kimlexi.jpg" width="400" height="300" alt="Kimlexi" onclick="myFunction();mode('kimlexi.jpg');">
</input>
</div>
</center>
<!-- The Modal -->
<div id="myModal" class="modal">
<!-- Modal content -->
<div class="modal-content">
<span class="close">
<img src="x.png" width="40" height="40" alt="X">
</span>
<center>
<img id="myImage" src="" width="600" height="500" alt="Kimlexi">
</center>
</div>
</div>
</body>
CSS -
<style>
button {
background:transparent;
border:none;
outline:none;
display:block;
height:200px;
width:200px;
cursor:pointer;
}
/* The Modal (background) */
.modal {
display: none; /* Hidden by default */
position: fixed; /* Stay in place */
z-index: 1; /* Sit on top */
padding-top: 100px; /* Location of the box */
left: 0;
top: 0;
width: 100%; /* Full width */
height: 100%; /* Full height */
overflow: auto; /* Enable scroll if needed */
background-color: rgb(0,0,0); /* Fallback color */
background-color: rgba(0,0,0,0.4); /* Black w/ opacity */
}
/* Modal Content */
.modal-content {
background-color: #fefefe;
margin: auto;
padding: 20px;
border: 1px solid #888;
width: 80%;
}
/* The Close Button */
.close {
color: #aaaaaa;
float: right;
font-size: 28px;
font-weight: bold;
}
.close:hover,
.close:focus {
color: #000;
text-decoration: none;
cursor: pointer;
}
.floated_img
{
float: left;
}
</style>
答案 0 :(得分:0)
这里有两个问题。
mode('ScreenShot.png')
,
<h1>
<img>
的{{1}} src
处理程序,但从不实际打开模态! onclick
处理程序在上面的步骤1.4中被覆盖(它被覆盖,未添加),并且新事件处理程序(onclick
)仅使模式可见但不更改图像源。如果只设置一次btn.onclick = function() { modal.style.display = "block"; }
处理程序,会更容易。这是一个解决方案。
JS -
onclick
HTML -
function openModal(imgSrc)
{
document.getElementById("myImage").src = imgSrc;
document.getElementById("myModal").style.display = "block";
}
function closeModal() {
document.getElementById('myModal').style.display = "none";
}
// When the user clicks anywhere outside of the modal, close it
window.onclick = function(event) {
if (event.target == document.getElementById('myModal')) {
closeModal();
}
}