Question

此处测试图片： http://images.plurk.com/tn_4134189_bf54fe8e270ce41240d534b5133884ee.gif

我已尝试在互联网上找到多种解决方案，但没有可行的解决方案。

我正在使用以下代码段：

Url imageUrl = new Url("http://images.plurk.com/tn_4134189_bf54fe8e270ce41240d534b5133884ee.gif");
Bitmap image = BitmapFactory.decodeStream(imageUrl.openStream());

始终获取此日志：

DEBUG/skia(1441): --- decoder->decode returned false

有任何帮助吗？感谢。

编辑：

无法解码的图像也无法在WebView上显示。但是可以看看是否在浏览器中打开。

Answer 1

我有同样的问题，部分是由这个类修复的：

static class FlushedInputStream extends FilterInputStream {
public FlushedInputStream(InputStream inputStream) {
    super(inputStream);
}

@Override
public long skip(long n) throws IOException {
    long totalBytesSkipped = 0L;
    while (totalBytesSkipped < n) {
        long bytesSkipped = in.skip(n - totalBytesSkipped);
        if (bytesSkipped == 0L) {
              int byte = read();
              if (byte < 0) {
                  break;  // we reached EOF
              } else {
                  bytesSkipped = 1; // we read one byte
              }
       }
        totalBytesSkipped += bytesSkipped;
    }
    return totalBytesSkipped;
}

}

和

InputStream in = null;
    try {
        in = new java.net.URL(imageUrl).openStream();
        } catch (MalformedURLException e) {
        e.printStackTrace();
        } catch (IOException e) {
        e.printStackTrace();
        }
Bitmap image = BitmapFactory.decodeStream(new FlushedInputStream(in));

在大多数情况下它有所帮助，但这不是通用解决方案。有关更多信息，请参阅此bugreport。

祝你好运！

Answer 2

尝试将其作为临时解决方法：

首先添加以下类：

  public static class PlurkInputStream extends FilterInputStream {

    protected PlurkInputStream(InputStream in) {
        super(in);
    }

    @Override
    public int read(byte[] buffer, int offset, int count)
        throws IOException {
        int ret = super.read(buffer, offset, count);
        for ( int i = 2; i < buffer.length; i++ ) {
            if ( buffer[i - 2] == 0x2c && buffer[i - 1] == 0x05
                && buffer[i] == 0 ) {
                buffer[i - 1] = 0;
            }
        }
        return ret;
    }

}

然后使用PlurkInputStream包装原始流：

Bitmap bitmap = BitmapFactory.decodeStream(new PlurkInputStream(originalInputStream));

如果这有助于您，请告诉我。

修改

抱歉，请尝试使用以下版本：

for ( int i = 6; i < buffer.length - 4; i++ ) { if ( buffer[i] == 0x2c ) { if ( buffer[i + 2] == 0 && buffer[i + 1] > 0 && buffer[i + 1] <= 48 ) { buffer[i + 1] = 0; } if ( buffer[i + 4] == 0 && buffer[i + 3] > 0 && buffer[i + 3] <= 48 ) { buffer[i + 3] = 0; } } }

请注意，这不是有效的代码，也不是完整/正确的解决方案。它适用于大多数情况，但不是全部。

Answer 3

我尝试了所有的解决方案，但没有解决我的问题。经过一些测试，当互联网连接不稳定时，skia解码器失败的问题发生了很多。对我来说，强制重新下载图像解决了这个问题。

当图像尺寸较大时，问题也会更多。

使用循环将需要我最多2次重试，并且图像将被正确下载。

Bitmap bmp = null;
int retries = 0;
while(bmp == null){
    if (retries == 2){
        break;
    }
    bmp = GetBmpFromURL(String imageURL);
    Log.d(TAG,"Retry...");
    retries++;
}

Answer 4

这应该有效：

URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
connection.disconnect();
input.close();

myBitmap包含您的图片。

Answer 5

这是由于Android中的InputStream类中的错误。您可以在http://code.google.com/p/android/issues/detail?id=6066

找到有效的解决方法和错误说明

Answer 6

试试这个：

HttpGet httpRequest = new HttpGet(url);
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = (HttpResponse) httpclient.execute(httpRequest);
HttpEntity entity = response.getEntity();
BufferedHttpEntity bufferedHttpEntity = new BufferedHttpEntity(entity);
InputStream is = bufferedHttpEntity.getContent();
Drawable d = Drawable.createFromStream(is, "");
//or bitmap
//Bitmap b = BitmapFactory.decodeStream(is);

Answer 7

出于内存原因，您必须实现这样的BitmapFactory选项：

BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 4; // might try 8 also

主下载位图功能可能是这样的：

Bitmap downloadBitmap(String url) {

    final HttpClient client = AndroidHttpClient.newInstance("Android");
    final HttpGet getRequest = new HttpGet(url);

    try {
        HttpResponse response = client.execute(getRequest);
        final int statusCode = response.getStatusLine().getStatusCode();
        if (statusCode != HttpStatus.SC_OK) {
            if(DEBUG)Log.w("ImageDownloader", "Error " + statusCode +
                    " while retrieving bitmap from " + url);
            return null;
        }

        final HttpEntity entity = response.getEntity();
        if (entity != null) {
            InputStream inputStream = null;
            try {

                inputStream = entity.getContent();
                BitmapFactory.Options options = new BitmapFactory.Options();
                options.inSampleSize = 4; // might try 8 also
                return BitmapFactory.decodeStream(new FlushedInputStream(inputStream),null,options);

            } finally {
                if (inputStream != null) {
                    inputStream.close();
                }
                entity.consumeContent();
            }
        }
    } catch (IOException e) {
        getRequest.abort();
        if(DEBUG)Log.w(TAG, "I/O error while retrieving bitmap from " + url, e);
    } catch (IllegalStateException e) {
        getRequest.abort();
        if(DEBUG)Log.w(TAG, "Incorrect URL: " + url);
    } catch (Exception e) {
        getRequest.abort();
        if(DEBUG)Log.w(TAG, "Error while retrieving bitmap from " + url, e);
    } finally {
        if ((client instanceof AndroidHttpClient)) {
            ((AndroidHttpClient) client).close();
        }
    }
    return null;
}

也许你必须像这样实现AsyncTask： http://android-developers.blogspot.com/2010/07/multithreading-for-performance.html

Answer 8

对我来说，问题在于图像的颜色类型：您的图像是彩色= CYMK不是RGB

Answer 9

也许这不是你的情况，但可能是你试图用CMYK颜色空间而不是RGB颜色空间解码图像。 Android不支持CMYK图像，如this one，即使在Android网络浏览器中也不会显示。详细了解此here：

Unable to load JPEG-image with BitmapFactory.decodeFile. Returns null

BitmapFactory.decodeStream始终返回null，skia解码器显示decode返回false

9 个答案: