Question

我有一个json数组

<div>
  <form id="form" method="POST" action="your link">
    . . . . .
    <p>
      <input type="submit" value="Pay">
    </p>
  </form>
</div>

如果用户使用任何ssn或名称或数字搜索，我想获取id值。搜索输入可能不是单个值，这意味着它可能是ssn和name的组合，或者可能是name，ssn和number 。任何名称编号的组合，ssn可能是输入。如果输入匹配使用php。我必须得到id值。我使用xpath for xml但我想搜索fron json.can有人建议我有任何想法..谢谢你。 ..

Answer 1

要通过分析JSON字符串来搜索用户ID，请使用以下方法array_filter和array_intersect_assoc函数：

$json_str = '[ { "id":1.25, "name":"rose", "Number":15, "SSN":[ 12345, 3455 ] }, { "id":1.15, "name":"orchid", "Number":7, "SSN":[ 12345, 3455 ] }]';
$decoded = json_decode($json_str, true);

// base search structure
$search_structure = ['name' => "", 'Number' => 0];

// let's say, the following inputs have come from API (some of them may be empty or omitted)
$number = 7;
$ssn = "3455";

if ($number && is_numeric($number)) $search_structure['Number'] = $number;
$search_structure = array_filter($search_structure); // filtering out empty params
$count_params = count($search_structure);
$user_id = 0;

foreach ($decoded as $item) {
    if ($count_params == count(array_intersect_assoc($search_structure, $item))) {
        if (!$ssn || ($ssn && in_array($ssn, $item['SSN']))) {
            $user_id = $item['id'];
            break;
        }
    }
}

print_r(($user_id)? "User id: $user_id" : "User with specified params not found!");

输出：

User id: 1.15

Answer 2

让$ json包含一个数组字符串

$ar = json_decode($json, true);
$id = false;
foreach ($ar as $i) 
   if ($i["name"] == "rose" and  $i["Number"] == 15)
      { $id = $i["id"]; break; }
if ($id !== false) { 
   // use $id
}

Answer 3

优选地，convert the json data to native PHP Object然后使用foreach，遍历对象并提取与给定SSN号匹配的对象的ID。提取的结果将分配给一个数组。下面是一个评论过程：1可能的解决方法：

    <?php

        // WE ASSUME, JUST FOR TESTING PURPOSES THAT THE SSN NUMBER WE ARE LOOKING FOR IS 4567
        $ssnNumber  = 4567; //3455;

        // CREATE A NEW ARRAY VARIABLE TO HOLD THE IDs YOU DESIRE & INITIALIZE IT TO AN EMPTY ARRAY
        $arrIDS     = array();
        $jsonData   = '[
              {
                 "id"       :1.25,
                 "name"     :"rose",
                 "Number"   :15,
                 "SSN"      :[
                        12345,
                        3455
                 ]
              },

              {
                 "id"       :1.15,
                 "name"     :"orchid",
                 "Number"   :7,
                 "SSN"      :[
                        12345,
                        3455
                 ]
              },

              {
                 "id"       :1.75,
                 "name"     :"orchid",
                 "Number"   :79,
                 "SSN"      :[
                        4567,
                        89012
                 ]
              }
            ]';
        // CONVERT $jsonData TO NATIVE PHP OBJECT
        $objJson    = json_decode($jsonData);

        // LOOP THROUGH THE PHP OBJECT & TEST IF A GIVEN SSN EXIST.
        foreach($objJson as $key=>$data){
            // CHECK IF THE $data->SSN IS SET:
            if(isset($data->SSN) && is_array($data->SSN)){
                // CHECK IF THE SSN ARRAY CONTAINS THE GIVEN SSN NUMBER.
                if(in_array($ssnNumber, $data->SSN)){
                    $arrIDS[]   = $data->id;
                }
            }
        }
        var_dump($arrIDS);  // DISPLAY: array (size=1) 0 => float 1.75

或者，也可以将上述例程withina函数封装起来，以便重新使用，如下所示：

    <?php    
        function getIDBySSN($jsonData, $ssnNumber){
            $arrIDs     = array();
            $objJson    = json_decode($jsonData);
            // LOOP THROUGH THE PHP OBJECT & TEST IF A GIVEN SSN EXIST.
            foreach($objJson as $key=>$data){
                // CHECK IF THE $data->SSN IS SET:
                if(isset($data->SSN) && is_array($data->SSN)){
                    // CHECK IF THE SSN ARRAY CONTAINS THE GIVEN SSN NUMBER.
                    if(in_array($ssnNumber, $data->SSN)){
                        $arrIDs[]   = $data->id;
                    }
                }
            }
            return $arrIDs;
        }

        var_dump(getIDBySSN($jsonData, $ssnNumber)); // PRODUCES THE SAME RESULT

测试HERE:

使用php动态搜索jsonarray多个值

3 个答案: